Answer:
<u>Anything less than 26, and greater than 74.</u>
Step-by-step explanation:
In normal distribution, the outlier is more than e ≈ 2.72 standard deviations above quartile 3, and e standard deviations below quartile 1. These quartiles are divisions that make up what is known as the innerquartile range(IQR). Which defines the variability of a data set given by IQR = Q3-Q1.
Given that the mean of this data is 50, and the standard deviation is 8.
Our outliers are anything less than 26, and anything greater than 74. Since outliers are anything outside the mean plus and minus the standard deviation times 3
Answer:
In this case, we have a linear equation:
y = 3*x - 2
And we want to graph this in the interval –3 ≤ x ≤ 3
Because this is a linear equation, to graph it we can just evaluate the equation in both extremes of the interval to find the two extremes of the graph.
Then we just need to connect these points with a segment, and that will be the graph of our equation.
Because the symbols used are: ≤
We need to graph the extremes with a black dot, which means that the point is included in the graph (would be different if we had -3 < x < 3)
The first extreme is when we have x = -3
y = 3*(-3) - 2 = -9 - 2 = -11
Then we have one extreme at (-3, -11)
The other is when x = 3
y = 3*3 - 2 = 9 - 2 = 7
Then the other extreme is at (3, 7)
Now we just need to draw these two points and connect them, an example of this can be seen in the image below:
Answer:
![\[3x+\frac{2}{3}\]](https://tex.z-dn.net/?f=%5C%5B3x%2B%5Cfrac%7B2%7D%7B3%7D%5C%5D)
Step-by-step explanation:
![\[f(x)=x-\frac{1}{3}\]](https://tex.z-dn.net/?f=%5C%5Bf%28x%29%3Dx-%5Cfrac%7B1%7D%7B3%7D%5C%5D)
![\[g(x)=3x+1\]](https://tex.z-dn.net/?f=%5C%5Bg%28x%29%3D3x%2B1%5C%5D)
Hence, ![\[(f o g)(x)=f(3x+1)\]](https://tex.z-dn.net/?f=%5C%5B%28f%20o%20g%29%28x%29%3Df%283x%2B1%29%5C%5D)
But, ![\[f(3x+1)=(3x+1)-\frac{1}{3}\]](https://tex.z-dn.net/?f=%5C%5Bf%283x%2B1%29%3D%283x%2B1%29-%5Cfrac%7B1%7D%7B3%7D%5C%5D)
Simplifying,
![\[f(3x+1)=3x+(1-\frac{1}{3})\]](https://tex.z-dn.net/?f=%5C%5Bf%283x%2B1%29%3D3x%2B%281-%5Cfrac%7B1%7D%7B3%7D%29%5C%5D)
= ![\[f(3x+1)=3x+(\frac{3-1}{3})\]](https://tex.z-dn.net/?f=%5C%5Bf%283x%2B1%29%3D3x%2B%28%5Cfrac%7B3-1%7D%7B3%7D%29%5C%5D)
= ![\[f(3x+1)=3x+(\frac{2}{3})\]](https://tex.z-dn.net/?f=%5C%5Bf%283x%2B1%29%3D3x%2B%28%5Cfrac%7B2%7D%7B3%7D%29%5C%5D)
Hence, ![\[(f o g)(x)=3x+(\frac{2}{3})\]](https://tex.z-dn.net/?f=%5C%5B%28f%20o%20g%29%28x%29%3D3x%2B%28%5Cfrac%7B2%7D%7B3%7D%29%5C%5D)
Answer:
Option D: 900
Step-by-step explanation:
Please kindly check the attached files for further explanation.
Answer:
22 degrees
Step-by-step explanation:
AT y=0 t = -7
at y = 38000 t= -29
What is the difference in temperature
t(0) - t(3800) = -7 - (-29) = -7+29 = 22
The difference is 22 degrees
