Question

X is an integer and xFormula1" title="9\ \textless \ {x}^2\ \textless \ 99" alt="9\ \textless \ {x}^2\ \textless \ 99" align="absmiddle" class="latex-formula">
What is the maximum value of x minus the minimum value of x?

Answer 1

We have the number 81 as the largest perfect square in the range of the statement.
Since we have it as the largest square, then its largest possible modulus of "x" will be when $x^2 = 81$, that is, when $| x | = 9$.
Since it is the largest possible module, the rightmost number of the "0" in the line of integers, with the largest number being x = 9 and the leftmost number of the "0" in the line of integers, , Will be $x = - 9$ 

Therefore, the difference requested in the statement is:
$v = 9 - (- 9) \longrightarrow v = 9+9 \longrightarrow \boxed{\boxed{v = 18}}$