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dolphi86 [110]
3 years ago
14

X is an integer and

xFormula1" title="9\ \textless \ {x}^2\ \textless \ 99" alt="9\ \textless \ {x}^2\ \textless \ 99" align="absmiddle" class="latex-formula">
What is the maximum value of x minus the minimum value of x?
Mathematics
1 answer:
Nataly [62]3 years ago
7 0
<span>We have the number 81 as the largest perfect square in the range of the statement.
Since we have it as the largest square, then its largest possible modulus of "x" will be when </span>x^2 = 81<span>, that is, when </span>| x | = 9<span>.
Since it is the largest possible module, the rightmost number of the "0" in the line of integers, with the largest number being x = 9 and the leftmost number of the "0" in the line of integers, , Will be </span>x = - 9<span> 

Therefore, the difference requested in the statement is:
</span>v = 9 - (- 9) \longrightarrow v = 9+9 \longrightarrow \boxed{\boxed{v = 18}}
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Arah went to the grocery store and bought 4 loaves of bread and 1 gallon of milk for $12. The next week, Sarah bought 2 loaves o
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Answer:

Here, b represents one loaf of bread and m represents the one gallon of milk.

As per the statement:

Arah went to the grocery store and bought 4 loaves of bread and 1 gallon of milk for $12.

⇒4b+m = 12  

It is also given that the next week, Sarah bought 2 loaves of bread and 3 gallons of milk for $13.50.

⇒2b+3m = 13.50

Then; system of equation :

4b+m = 12                   .....[1]

2b+3m = 13.50           .....[2]

Solve for b and m using above system of equations.

Multiply equation [2] by 2 we get;

4b+6m = 27              .....[3]

Subtract equation [1] from [3] we get;

4b+6m - 4b -m= 27-12

Combine like terms;

5m= 15

Divide both sides by 5 we get;

m = $3

Substitute the value of m in equation [1] we get;

4b+3 = 12

Subtract 3 from both sides we get;

4b=9

Divide both sides by 4 we get;

b = $2.25

Therefore, cost of one loaf of bread (b) and one gallon of milk (m) are:

$2.25 ad $3



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