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muminat
3 years ago
5

A researcher wants to compare the effect of a new type of shampoo on hair condition. The researcher believes that men and women

may react to the shampoo differently. Additionally, the researcher believes that the shampoo will react differently on hair that is dyed. The subjects are split into four groups: men who dye their hair; men who do not dye their hair; women who dye their hair; women who do not dye their hair. Subjects in each group are randomly assigned to the new shampoo and the old shampoo. This experiment
a. has three factors (shampoo type, gender, whether hair is dyed).
b. has two factors (shampoo type and whether hair is dyed) blocked by gender
c. has one factor (shampoo type), blocked by gender and whether hair is dyed.
d. has two factors (gender and whether hair is dyed) blocked by shampoo type.
e. is completely randomized. (Old exam question)
Mathematics
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

This experiment has three factors (shampoo type, gender, whether hair is dyed)

Step-by-step explanation:

the researcher is trying to make a comparison between an old shampoo and a new on and also was gender sensitive as she considers their hair coloration too because it affects the result slightly.

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What is the interquartile range for the data set?
yarga [219]
To solve this problem you must apply the proccedure shown below:

 1-  By definition, the formula for calculate the i<span>nterquartile range is

 I</span><span>nterquartile range=Q3-Q1

 Where Q1 is the lower quartile and Q3 is the upper quartile.

 2-Keeping this on mind, you have:

 </span>Interquartile range=Q3-Q1
<span>
 Q3=245
 Q1=201

 </span>Interquartile range=245-201
 Interquartile range=44
<span>
 Therefore, the answer is: 44

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6 0
3 years ago
Help Me PLZUse the diagram below to answer the questions that follow. Lines a and b are parallel, LaǁLb. Point L is midpoint of
horrorfan [7]

Answer:

Use the transversal

Step-by-step explanation:

Line/transversal DG splits everything into 180° sections. Since angle DFH is 98°, DFO is 180°-98°. OFL is 98° since it is a transversal split. LFH is 180°-98°.  

7 0
3 years ago
Find the sum of the first 70 terms of the sequence –6, –3, 0, 3, 6, ...
Lostsunrise [7]
Hello : 
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sum = n/2 (U1 +U70)
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7 0
4 years ago
Read 2 more answers
For the vectors Bold uequalsleft angle negative 8 comma 0 comma 1 right angleand Bold vequalsleft angle 1 comma 3 comma negative
trapecia [35]

Answer:

Step-by-step explanation:

Given that there are two vectors U = (-8,0,1)

V = (1,3,-3)

To find projection of u on V and also projection of V on U

First let us find the dot product U and V

U.V = -8(1)+0(3)+1(-3)\\= -11

Projection of U on V =\frac{U.V}{|V|} \\=\frac{-11}{\sqrt{1+9+9} } \\=\frac{-11}{\sqrt{19} }

Similarly projection of V on U

=\frac{U.V}{|U|} \\=\frac{-11}{\sqrt{64+0+1} } \\=\frac{-11}{\sqrt{65} }

4 0
4 years ago
A random sample of 5120 permanent dwellings on an entire reservation showed that 1627 were traditional hogans.
krek1111 [17]

Answer:

a) \hat p=\frac{1627}{5120}=0.3178

b)The 99% confidence interval would be given by (0.301;0.355)

Step-by-step explanation:

1) Notation and definitions

X=1627 number of permanent dwellings on the entire reservation that are traditional hogans.

n=5120 random sample taken

\hat p=\frac{1627}{5120}=0.318 estimated proportion of permanent dwellings on the entire reservation that are traditional hogans.

p true population proportion of permanent dwellings on the entire reservation that are traditional hogans.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

Part a

The point of estimate for p=the proportion of all permanent dwellings on the entire reservation that are traditional hogans is given by:

\hat p=\frac{1627}{5120}=0.3178

Part b

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.318 - 2.58\sqrt{\frac{0.318(1-0.318)}{5120}}=0.301

0.318 + 2.58\sqrt{\frac{0.318(1-0.318)}{5120}}=0.335

The 99% confidence interval would be given by (0.301;0.355)

8 0
4 years ago
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