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Mathematics

2 answers:

Yuri [45]3 years ago

7 0

Answer:

Jodi and Mariah are sisters. Jodi is three years older than Mariah. Using one variable, write an expression to represent the sum of their ages. Make sure to explain what your variable represents.

(3+x)+x

Step-by-step explanation:

x=Mariah

lapo4ka [179]3 years ago

3 0

Answer

x + (3 + x)

Step-by-step explanation:

Let Mariah's age be x, if so since Jodi is 3 years older than Mariah, then Jodi's age will be 3 + x

Then the sum of their ages will be x + (3 + x)

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Makovka662 [10]

I would put 2 as the answer

4 0

4 years ago

X = y = m ∠ H = m ∠ G =

Lorico [155]

Answer:

x=53

y=26

H=106

G=93

Step-by-step explanation:

By the inscribed quadrilateral conjecture:

$2x+(x+21)=180\\(3y+9)+(4y-11)=180\\3x+21=180\\3x=159\\x=53\\7y-2=180\\7y=182\\y=26\\H=2(53)=106\\G=(4(26)-11)=104-11=93$

Hope this helps!

4 0

4 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

-------------------------------------------------------------

$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$