Answer:

Step-by-step explanation:
Given: There are 2 classes of 25 students.
13 play basketball
11 play baseball.
4 play neither of sports.
Lets assume basketball as "a" and baseball as "b".
We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)
As given total number of student is 25
Now, subtituting the values in the formula.
⇒P(a∪b)= 
taking LCD as 25 to solve.
⇒P(a∪b)= 
∴ P(a∪b)= 
Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is
.
I'll assume those are squares. We know D is an identity:

Dividing through by


That's A.
Dividing the original through by


Not quite B, wrong sign on tangent.
C has the wrong sign on cosine squared as well.
Identities: A & D
<span>21-3y=36-6y +3y
21 = 36 - 3y -36
-36+21 = -3y
- 15 = - 3y ÷ -3
5 = y
Choice: B
</span>
Answer:
2,3,6
Step-by-step explanation:
those are the only positive factors in there
Answer:
a=70 b=.16 c=350
Step-by-step explanation:
50 messages is 8 dollars