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emmainna [20.7K]
3 years ago
7

Find the distance between points M(-7,5) and Z(2,-3)

Mathematics
1 answer:
julsineya [31]3 years ago
8 0

Hey there! I'm happy to help!

To find the distance between two points, you find the difference between the x values, square that, find the difference between the y values, square that, add the two numbers you got, and then find the square root.

We find the difference between the x values.

-7-2=-9

Square it.

-9²=81

We find the difference between the y-values.

5--3

5+3=8

We square it.

8²=64

We add the numbers we got.

81+64=145

We square root.

√145≈12.04

This formula comes from the Pythagorean Theorem! Now you can find the distance between any two points! Have a wonderful day! :D

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a) find center of mass of a solid of constant density bounded below by the paraboloid z=x^2+y^2 and above by the plane z=4.(b) F
slava [35]

Answer: x-bar = y-bar = 0 whereas z-bar = 8/3

               M= (c^2)/8 which is intern equal to 2\sqrt{2}

Step-by-step explanation:

           Find the area, by setting the limits as

               = 4\cdot \int _0^{\frac{\pi }{2}}\int _0^2\int _{r^2}^4\:rdzdrd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}\int _0^2r\cdot \:4-r^3drd\theta

                =4\cdot \int _0^{\frac{\pi }{2}}4d\theta

                 =8\pi

Therefore;

Mxy=  \int _0^{2\pi }\int _0^2\int _{r^2}^4\:zrdzdrd\theta

       z-bar = 8/3

M= 8\pi dividing it into two volume gives us = 4\pi

means  4\pi =\int _0^{2\pi }\int _0^{\sqrt{c}}\int _r^c\:rdzdrd\theta

             4\pi =\left(\pi c^2-2\pi \frac{c^{\frac{3}{2}}}{3}\right)

              c=2\sqrt{2}

       

                 

                 

5 0
3 years ago
−3⋅
Katyanochek1 [597]

Answer:\frac{7^{15}}{3^{30}}

Step-by-step explanation:

hope it helps

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