The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
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Answer: A) 4.8 CM
Step-by-step explanation:
1. 79% Take 100 x 21%=21, then subtract 21 from 100 = 79
2. $138 Take 1200 x 11.5%= $138
Answer:
2 and remains the same
Step-by-step explanation:
First let’s express the total number of marbles as such:
y(yellow marbles) + r(red marbles)=23; y+r=23
now let’s express the relation of yellow marbles to red marbles:
y=2r(2 times red marbles) - 4(4 less marbles); y=2r-4
since we figured out what y equals, we can plug into the first equation we created:
(2r-4)+r=23
now solve for r:
2r-4+r=23
combine like terms
3r-4=23
add 4 to both sides
3r=27
divide both side by 3
r=9
plug r back into first equation and solve for y:
y+9=23
subtract 9
y=14
there are 9 red marbles and 14 yellow marbles!
