D i’m pretty sure; -5 x 2 is -10 x 3 = 30
Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
3xy -6x
just multiply 3x by y and 3x by -2
Step-by-step explanation:
the answer to your question with roster method is
(-5,-4,-3,-2 and -1)
Xmin:-10 Xmax:10 and Ymir:-10 Ymax:10
