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3 years ago

HELO HELO PLEASEE ASAP ASAPPPPPPP PLEASEEEE

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

6 0

Answer:the answer is D.

Step-by-step explanation:

5(x)- -3(y) is 8. Make the negative into a positive if the equation looks like that. 4x5=20 + 3x-3=-9 so 20+-9= 11

Lemur [1.5K]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Write .0296 in word form

TEA [102]

two hundred ninety-six ten thousandths

4 0

3 years ago

Over the summer Mr.Patel refilled a bird feeder 24 time using 6 cups of seeds each time.A bag of seeds holds 32 cups. How many b

nalin [4]

Answer:

The equation representing the problem is $x=\frac{24\times 6}{32}$ .

Mr. Patel used 5 bags of seeds.

Step-by-step explanation:

Given:

Number of times bird feeder refilled =24

Number of cups of seeds used each time = 6 cups

Number of seeds each bag holds = 32 cups.

We need to write the equation to represent the problem.

Solution.

Let the total number of bag of seed be 'x'.

First we will find the Total number of cups of seeds used.

Now we can say that;

Total number of cups of seeds used can be calculated by multiplying Number of times bird feeder refilled by Number of cups of seeds used each time.

framing in equation form we get;

Total number of cups of seeds used = $24\times6 \ cups$

Now We know that;

1 bag holds = 32 cups

Total number of bags required = $24\times6 \ cups$

So we can say that;

Total number of bags required is equal to Total number of cups of seeds used divided by number of seed hold by each bag.

framing in equation form we get;

$x=\frac{24\times 6}{32}$

Hence the equation representing the problem is $x=\frac{24\times 6}{32}$ .

On solving we get;

$x=4.5$

Since bags cannot be bought in half or in decimal value.

Hence we can say Mr. Patel used 5 bags of seeds.

7 0

3 years ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

3 years ago

In order to prepare for your summer bash, you go to the supermarket to buy hamburgers and

timofeeve [1]

The complete question is:

In order to prepare for your summer bash, you go to the supermarket to buy hamburgers and chicken. Hamburgers cost $2 per pound and chicken costs $3 per pound. You have no more than $30 to spend. You expect to purchase at least 3 pounds of hamburgers.

Write a system of inequalities to represent this situation.
Graph the system of inequalities on the grid.
Give three possible combinations for buying hamburgers and chicken for your summer bash.

Justify your answers

Answer:

A) System of inequalities:

2x + 3y ≤ 30

x ≥ 3

x ≥ 0

y ≥ 0

B) Graph: see the picture attached

C) Three possible combinations:

3 pounds of hamburgers and 8 pounds of chicken

3 pounds of hamburgers and 0 pounds of chicken

15 pounds of hamburgers and 0 pounds of chicken

Explanation:

A) Write the system of inequalities to represent this situaction.

1. Variables:

x: number of pound of hamburgers
y: number of pound of chicken

2. Costs:

x pounds of hamburgers at $2 per pound: 2x
y: pounds of chicken at $3 per pound: 3y

total cost: 2x + 3y

3. First constraint:

You have no more than $ 30 to spend: means that the cost of what you buy can be at most (less than or equal to) $ 30.

2x + 3y ≤ 30

4. Second constraint:

You expect to purchase at least 3 pounds of hamburgers: means that the number of pounds of hamburgers may be greater than or equal to 3.

x ≥ 3

5. Additional constraints:

Both, x and y cannot be negative: x, y ≥ 0

6. System of equations:

2x + 3y ≤ 30

x ≥ 3

x ≥ 0

y ≥ 0

B) Graph 

You have to graph all the constraints in a x-y coordinate system.

1. To graph 2x + 3y ≤ 30 graph the line 2x + 3y = 30

Choose the y-intercept and x-intercept.

x = 0 ⇒ 3y = 30 ⇒ y = 10 ⇒ point (0, 10)

y = 0 ⇒ 2x =30 ⇒ x = 15 ⇒ point (15, 0)

With two points you can draw the line

Clear y: y ≤ 10 - 2x/3. Since, the symbol is ≤ you shade the region below the line, and the line is included, so you draw it as as solid line.

2. To graph x ≥ 3 just draw the vertical line x = 3 and shade the region to the right of it. The points of the line are included (solid line).

3. The constraints x ≥ 0 and y ≥ 0 mean that the region is restricted to the first quadrant (including the positive axis).

4. The feasible solutions are the set of points inside the common regions (intersection).

With all that information the graph is the one attached. The feasible solutions is the region defined by the triangle with vertices (3,8), (3,0), and (15,0).

C) Give 3 possible combinations.

You can pick any three points inside the region, as long as the coordinates are integer numbers. For instance the 3 vertices are solutions:

(3, 8) ⇒ 3 pounds of hamburgers and 8 pounds of chicken

(3,0) ⇒ 3 pounds of hamburgers and 0 pounds of chicken

(15,0) ⇒ 15 pounds of hamburgers and 0 pounds of chicken

You could also prove that (5,4), 5 pounds of hamburgers and 4 pounds of chicken meet, the inequalities.

This is how you prove it:

5 ≥ 0
5 ≥ 3
4 ≥ 0
2(5) + 3(4) = 10 + 12 = 22 ≤ 30

And you can do the same for any pairs to verify whether they are solution or not.

7 0

3 years ago

What is the value of b in the equation brainly (y^-9)^b=y^45?

riadik2000 [5.3K]

Answer:

its -5 just took the test

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers