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LekaFEV [45]
3 years ago
14

PLEASE HELP MEEEEEE​

Mathematics
2 answers:
jeka57 [31]3 years ago
6 0

Answer:

Ok what you can try to do is multiply, then, subtract, add , or do division to see what you get. So try doing all of that then see what you're answer is.

Step-by-step explanation:

pogonyaev3 years ago
3 0
C. multiply 9 times 2= 18 x3 =54
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Two buses are traveling to a state park. One bus leaves the terminal at 4:00 p.m. and travels at 40 miles per hour. The second b
kotykmax [81]
The answer would be 9 pm
5 0
3 years ago
13 is 6 1/2% of what number?
mylen [45]

Answer:

200

Step-by-step explanation:

3 0
1 year ago
The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

P(\frac{B'}{A}) = \frac{P(B'\cap A)}{P(A)} = \frac{0.4\times 0.8}{0.8} = 0.4

Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

= 0.4 x 0.4 = 0.16

P({A}'\cap {B}') = 0.16

i)

The probability that at least one of them is on time

P(A\cup B) = 1- P({A}'\cap {B}')  

=  1 - 0.16 = 0.84

ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
3 years ago
Please please please please help
Sidana [21]

Answer:

I guess its the first one

Step-by-step explanation:

I think they're asking which one doesn't look like a regular shape. Tbh I have no idea

7 0
3 years ago
Read 2 more answers
WILL MARK BRSINLIEST ANSWER IF GOTTEN RIGHT
Marianna [84]

Answer:

16.8km

Step-by-step explanation:

Arc length = 2πr(θ/360)

=2π(8)(120/360)

=16.7551608191

≈16.8km

8 0
3 years ago
Read 2 more answers
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