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svetoff [14.1K]
4 years ago
14

Can somebody explain to me how to solve this problem? I'm confused

Mathematics
1 answer:
navik [9.2K]4 years ago
8 0

Step-by-step explanation:

g(x) = f(2x), so g(x) is f(x) compressed by a factor of 2.

So if the domain of f(x) is [1, 5], then the domain of g(x) is [1/2, 5/2].

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At a college, 71% of courses have final exams and 45% of courses require research papers. Suppose that 26% of courses have a res
Degger [83]

Answer:

.9 or 90%

.1 or 10%

Step-by-step explanation:

E= Exam

P=Paper

E= .71

P= .45

E∩P=.26

A.) E∪P=?

E∪P= E+P-E∩P

.71+.45-.26= .9

B.) E'∩P' = (E∪P)'

(E∪P)' = 1-.9 = .1

3 0
3 years ago
Which is greater 3.75 3.750
guapka [62]

Answer:

None

Step-by-step explanation:

They are the same number

5 0
3 years ago
In angle STU, u = 890 cm, t = 810 cm and angle T=38°. Find all possible values of angle U, to the nearest degree.
erastova [34]

Answer:

754435.345345435.43.5435435454.35.34.543534.5.43.5.43.545

Step-by-step explanation:

7 0
3 years ago
A rectangular area is to be fenced in with 300 feet of chicken wire. find the maximum area that can be enclosed.
GarryVolchara [31]
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.

2(x+y) = 300
x+y = 150
y = 150-x

A=x(150-x) <--(substitution)

The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150

So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.

A=75(150-75)
A=75*75
A=5625

So the maximum area that can be enclosed is 5625 square feet.
6 0
3 years ago
Which of the following numbers is greatest, or furthest to the right on the number line? {56, 39, 74, 81, 62}
Dimas [21]
The greatest number is 81
4 0
3 years ago
Read 2 more answers
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