Answer:
The python code is given below with lists defined.
Explanation:
import sys
def isEven(n) :
return ((n % 2) == 0) //for even items
numbers = sys.argv[1].split(',')
for i in range(0,len(numbers)):
numbers[i]= int(numbers[i])
even = []
odd = []
for i in numbers:
if isEven(i):
even.append(i) #adds i to even list if it is even
else:
odd.append(i) #adds i to odd list if not even (odd)
print(odd)
print(even)
Answer:
True.
Explanation:
An investigator would like to do an internet-based college student survey to gather data regarding their behavior as well as drug use. Even so, specific identifications are still not gathered and IP addresses might be available in the set of data. Damage threat must be assessed both by the magnitude (or severity) and the likelihood (or likelihood) of the hurt.
<span>A chipset which forms an interface between the CPU's front-side bus, main memory, and peripheral buses. Non-volatile memory chips (usually Flash ROM in modern motherboards) containing the system's firmware or BIOS. A clock generator which produces the system clock signal to synchronize the various components.</span>
Answer:
A. 0.0450
B. 4
C. 0.25
D. 37.68
E. 6Hz
F. -0.523
G. 1.5m/s
H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
I. -1.67m/s.
Explanation:
Given the equation:
y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)
Standard wave equation:
y(x, t)=Asin(kx−ωt+ϕ)
a.) Amplitude = 0.0450
b.) Wave number = 1/ λ
λ=2π/k
From the equation k = 25.12
Wavelength(λ ) = 2π/25.12 = 0.25
Wave number (1/0.25) = 4
c.) Wavelength(λ ) = 2π/25.12 = 0.25
d.) Angular frequency(ω)
ωt = 37.68t
ω = 37.68
E.) Frequency (f)
ω = 2πf
f = ω/2π
f = 37.68/6.28
f = 6Hz
f.) Phase angle(ϕ) = -0.523
g.) Wave propagation speed :
ω/k=37.68/25.12=1.5m/s
h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.
In the Cell 'H13' of Sheet 'Payroll Data', the 'Formula' was not set to 'G13-B13*$B$24'.
