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BabaBlast [244]

3 years ago

13

If you receive a $4,500 in gift money and deposited into a savings account that pays 2.85% simple interest. How much will you ha

ve in the savings after 3 years?

1 answer:

marusya05 [52]3 years ago

3 0

$4,884.75 I hope this helps you sorry if you needed full math

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HURRY!!!!!!!!!<br><br> Given P(5,10,8) and Q(7,11,10), find the midpoint of the segment PQ.

rusak2 [61]

Answer:

$P_{m}=(6,10.5,9)$

Step-by-step explanation:

The mid point can be found with the formula

$P_{m}=(\frac{x_{1}+x_{2} }{2},\frac{y_{1} +y_{2} }{2} ,\frac{z_{1}+z_{2} }{2} )$

The given coordinates are $P(5,10,8)$ and $Q(7,11,10)$ .

Replacing coordinates in the formula, we have

$P_{m}=(\frac{5+7}{2},\frac{10+11 }{2} ,\frac{8+10}{2} )=(\frac{12}{2},\frac{21 }{2} ,\frac{18}{2} )\\P_{m}=(6,10.5,9)$

Therefore, the mid point of the segment PQ is $P_{m}=(6,10.5,9)$

4 0

3 years ago

If you enter the formula =A2*(1+$A$1) in cell B2 and then copy cell B2 to C2, the numerical result in cell

denis-greek [22]

It’s is b 121 . Gang gang

6 0

3 years ago

What is the reciprocal of<br> 8/5

azamat

Answer:

0.025

Step-by-step explanation:

7 0

3 years ago

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The greatest common factor of 3m2n + 12mn2 is

Karolina [17]

$3m^2n + 12mn^2=3mn\cdot(m+4n)$

6 0

3 years ago

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What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

3 years ago

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