1) y= - 2x² + 8x. It's a parabola open downward (a<0)
2) x - 2.23.y + 10.34 = 0 . Re-write it : y = (x/2.23) + (10.34/2.23), a linear equation.
To find the intersections between 1) & 2), let 1) = 2)
-2x² + 8x = (x/2.23) + (10.34/2.23)
-2x² + 8x - (x/2.23) - (10.34/2.23) =0 ; solve this quadratic for x values:
x' (that is A) = 0.772 & x" (that is B) = 3. (these are the values of x-intercept (parabola with line). To calculate the y-values, plug x' & x' in the equation:
for x' = 0.772, y = 0.34 → B(0.772 , 0.34)
for x" = 3, y = 0.016 → A(3 , 0.O16)
So B IS AT 0.34 Unit from the ground
Answer:
9 hours
Step-by-step explanation:
1 chapter ≈ .5 hour
18 x .5 = 9
3,-2 is the right answer i think
Answer:
3−y
2. 8
4.2bh
Step-by-step explanation:
5(2x+y)=15
2 Divide both sides by 55.
2x+y=\frac{15}{5}2x+y=
5
15
3 Simplify \frac{15}{5}
5
15
to 33.
2x+y=32x+y=3
4 Subtract yy from both sides.
2x=3-y2x=3−y
5 Divide both sides by 22.
x=\frac{3-y}{2}x=
2
1. 3−y
2. 8
2.Add 2y2y to both sides.
x=-8+2yx=−8+2y
2 Regroup terms.
x=2y-8x=2y−8
