Answer:
FALSE
Step-by-step explanation:
A tessellation refest to a shape that is repeated over and over again covering a plane without any gaps or overlaps. The statement is false given that regular tessellations use only one polygon. Semi-regular tessellations are created with more than one type of regular polygon.
For this case the first thing we must observe is that the mass increases 0.4 grams when the diameter increases 1 millimeter.
Therefore, the slope of the line is given by:
m = 0.4
Thus, the function that best suits the table is given by:
f (x) = -4 + 0.4x
For example, for x = 20 we have:
f (20) = -4 + 0.4 (20)
f (20) = -4 + 8
f (20) = 4
The result, matches the table.
Answer:
The function that is best represented by the scatter plot is:
f (x) = -4 + 0.4x
Answer:
Ok hi
Step-by-step explanation:
I’m not 100% sure but it could be 225 and 328. Adding those together you get a sum of 553.
Hope this helped! Mark me brainliest if you’d like, im tryna get too expert!
Answer:
The margin of error (E) 
Step-by-step explanation:
Given,
mean 
standard deviation 
sample size 

Critical value


Critical value 


The margin of error (E) 


Hence, The margin of error (E) 
Complete question is attached in below.