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Vikki [24]
2 years ago
8

Find the AREA of the cow pasture when x = 4 yards. 30x 20x

Mathematics
1 answer:
andre [41]2 years ago
8 0
120
80
Can I get brainliest?
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210 to 35whats the percent of increase or decrease
oee [108]

Answer:

25% of 210:

73.5

-----------------

175% of 210:

83.33333333 ~~ (on and on forever)

Step-by-step explanation:


4 0
3 years ago
Line l is defined by the equation y – 5x = 4 and line w is defined by the equation 10y + 2x + 20 = 0. if line k does not interse
Sliva [168]
Slope of line l (m1)=5
Slope of line w(m2)=-1/5
Since,m1×m2=-1 , line 'l' and 'w' are perpendicular.
Since line 'k' doesn't intersect line 'l' ,they must be parallel b'coz they are in the same plane as well.
Here, 'l' is perpendicular to 'w' and parallel to 'k'....so w and k must be perpendicular to each other.
It can be proven:
Since l and k are parallel, their slopes are equal.
So, slope of k (m3)=5
Since m3×m2=-1 ,w and k are perpendicular.
Hence, angle between w and k is 90°
7 0
3 years ago
PLEASE HELP ASAP! Answer + explanations :(
lukranit [14]

Uhm- What are you needing help on? Because there is no pic or numbers-

3 0
3 years ago
The equation <img src="https://tex.z-dn.net/?f=2m%5E%7B2%7D-1m-8%3D0" id="TexFormula1" title="2m^{2}-1m-8=0" alt="2m^{2}-1m-8=0"
Elza [17]

Answer:

  • N = 1
  • M = 4
  • D = 65

Step-by-step explanation:

The given equation is of the form ...

  ax² +bx +c = 0

where a=2, b=-1, c=-8.

The quadratic formula gives the solution to the above equation as ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

So, for your equation, the solution is ...

  m=\dfrac{-(-1)\pm\sqrt{(-1)^2-4(2)(-8)}}{2(2)}=\dfrac{1\pm\sqrt{65}}{4}

Comparing this to the form ...

  m=\dfrac{N\pm\sqrt{D}}{M}

we see ...

  • N = 1
  • M = 4
  • D = 65
3 0
3 years ago
Given any two numbers, which is greater, the LCM of the numbers or the GCF of the numbers? Why?
Cloud [144]
LCM always has to be bigger or the same than both numbers. HCF always has to be smaller as a factor has to fit exactly in the original number. So LCM will always be greater
8 0
3 years ago
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