Find the AREA of the cow pasture when x = 4 yards. <br><br> 30x <br> 20x

A man bought 250 electric lanterns in the united States of America for $5000. he sold them them in lagos at 1,920 naira each. at

Maurinko [17]

Answer: 4166.67$

Step-by-step explanation:

1920 x 250 = amount

Amount = 120%

Cost price = 100%

1920 x 250= 120%

Cost price = 100%

Cross multiply and divide both side by 120

1920 x 250 x 100/120 = price

Exchange rate = cost in #/cost in $

= (1920 x 250 x 5/6)/(5000)

= (96 x 5/6) = 16 x 5= 80

Exchange rate then was 80 to 1$

The sales will be 400000/96 = 4166.67$

7 0

3 years ago

Read 2 more answers

An automobile with 0.279 m radius tires travels 65000 km before wearing them out. How many revolutions do the tires make, neglec

bija089 [108]

Answer:

Revolutions=37079108.61 rev

Step-by-step explanation:

First if all we have to make the units same to calculate the revolutions

Since distance gis gien in km and radius is given in m we will covert distance to m first.

Distance =S=65000km

Distance=S=65000km*1000m/km

Distance = S= 65000000m

Formula:

S=rθ

where

S is the distance

r is the radius

θ is the revolution in radian

θ=S/r

θ=65000000/0.279

θ=232974910.4 rad

Revolutions=θ/2π

Revolutions=232974910.4/2π

Revolutions=37079108.61 rev

7 0

3 years ago

Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th

xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

$P:(x - 1)^2 + (y + 6)^2 = 9$

$Q:(x + 4)^2 + (y + 14)^2 = 4$

Solving (a): The distance between both

The equation of a circle is:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$Center: (h,k)$

$Radius:r$

P and Q can be rewritten as:

$P:(x - 1)^2 + (y + 6)^2 = 3^2$

$Q:(x + 4)^2 + (y + 14)^2 = 2^2$

So, for P:

$Center = (1,-6)$

$r = 3$

For Q:

$Center = (-4,-14)$

$r = 2$

The distance between them is:

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2$

Where:

$Center = (1,-6)$ --- $(x_1,y_1)$

$Center = (-4,-14)$ --- $(x_2,y_2)$

So:

$d = \sqrt{(1 - -4)^2 + (-6 - -14)^2$

$d = \sqrt{(5)^2 + (8)^2$

$d = \sqrt{25 + 64$

$d = \sqrt{89$

$d = 9.4$

Solving (b): The radius;

In (a), we have:

$r = 3$ --- circle P

$r = 2$ --- circle Q

By comparison

$2 < 3$

<em>Hence, circle Q has a smaller radius</em>

4 0

3 years ago

Find the missing side of the right triangle

o-na [289]

Answer:

Step-by-step explanation:

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have

$leg=3,\ leg=x,\ hypotenuse=\sqrt{10}$

Substitute:

$3^2+x^2=(\sqrt{10})^2$

$9+x^2=10$ <em>subtract 9 from both sides</em>

$9-9+x^2=10-9$

$x^2=1\to x=\sqrt1\\\\x=1$

7 0

3 years ago

X/72 = 135/90 what is x?

enot [183]

Hey! I'll provide the steps required.

First, solved the proportion by cross multiplication.

$X(90) = (135)(72)$

Then use the commutative property to reorder the terms as well as multiply the numbers.

90x = 9720

Finally, divide it by 90.

x = 108

5 0

3 years ago

Find the AREA of the cow pasture when x = 4 yards. 30x 20x