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zheka24 [161]
4 years ago
13

[MA5T10 E] Name the property being illustrated.

Mathematics
2 answers:
Elena-2011 [213]4 years ago
8 0
Answer: C). Distributive property
Bumek [7]4 years ago
4 0
The property shown here is the distributive property

You can see that you have multiplied the 45 by both 25 and 5, and subtracting both of those values from each other. Even though it is a different way of writing, the final answer is the same.
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Lizzie has 30 coins that total $4.80. All of her coins are dimes, D, and quarters, Q. Algebraically determine how many of each t
Gnom [1K]

Lizzie has 18 dimes and 12 quarters

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that LIzzie has 30 coins

number of dimes + number of quarters = 30

d + q = 30 ---- eqn 1

Also given that the coins total $ 4.80

number of dimes x  value of 1 dime + number of quarters x  value of 1 quarter = 4.80

d \times 0.10 + q \times 0.25 = 4.80

0.1d + 0.25q = 4.8 ------ eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 30 - q ---- eqn 3

Substitute eqn 3 in eqn 2

0.1(30 - q) + 0.25q = 4.8

3 - 0.1q + 0.25q = 4.8

0.15q = 1.8

<h3>q = 12</h3>

From eqn 3,

d = 30 - 12

<h3>d = 18</h3>

Thus she has 18 dimes and 12 quarters

6 0
4 years ago
Simplify each expression -5r (3r^2)​
Evgen [1.6K]

Answer:

The answer you're looking for is

-5r (3r^2) = -45

Step-by-step explanation:

7 0
4 years ago
The square root of 11.737476 has ____ decimal place ​
loris [4]

Answer:

3 decimal places

Step-by-step explanation:

square root of 11.737476 is 3.426

8 0
3 years ago
Read 2 more answers
A grain of sand has a mass of 2.6 × 10–3 gram. A grain of salt has a mass of 6.5 × 10–2 gram. How many times greater is the mass
myrzilka [38]

Answer:

C

Step-by-step explanation:

2.6 x10^-3= .0026

6.5 x10^-2=.065

.065/.0026=25

5 0
3 years ago
50/117 in simplest form
Daniel [21]
It remains the same. \frac{50}{117} cannot be simplified
6 0
3 years ago
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