The equation is linear, as you can write
An integrating factor would be
Multiplying both sides of the ODE by this yields
where the LHS is a derivative:
![\dfrac{\mathrm d}{\mathrm dx}\left[x^{1/3}y\right]=4x^{1/3}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5Bx%5E%7B1%2F3%7Dy%5Cright%5D%3D4x%5E%7B1%2F3%7D)
Integrating both sides, we get
I’m pretty sure that’s true.
Answer:
x=√2, x=-√2, x= 3 and x=-3
Step-by-step explanation:
We need to solve the equation x^4 - 11x^2+18=0
We can replace x^4 = u^2 and x^2 = u
So, the equation will become
u^2 -11u+18 = 0
Factorizing the above equation:
u^2 -9u-2u+18 =0
u(u-9)-2(u-9)=0
(u-2)(u-9)=0
u=2, u=9
As, u = x^2, Putting back the value:
x^2 =2 , x^2 =9
taking square roots:
√x^2 =√2 ,√x^2=√9
x=±√2 , x = ±3
so, x=√2, x=-√2, x= 3 and x=-3
Answer:
Step-by-step explanation:
Temperature needs to fall by 3 degrees
<span>∠BCA = 120 /2 = 60
answer
</span><span>∠BCA</span>
