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larisa86 [58]
4 years ago
13

Rewrite the equation of a straight line in a slope - intercept form x + 2y + 1 = 0

Mathematics
1 answer:
Liono4ka [1.6K]4 years ago
5 0

Answer:

y = -x/2 -1/2

Step-by-step explanation:

x + 2y + 1 = 0\\

Write in the y=mx+b form

2y =-x-1+0\\2y =-x-1

Divide both sides by 2

\frac{2y}{2} =\frac{-1x}{2} -\frac{1}{2} \\\\y = -\frac{x}{2} -\frac{1}{2}

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What are the coordinates of the y-intercept of the line who's equation is 12x + 13y =8???
Ierofanga [76]

Answer:

y-intercept = (0,  \frac{8}{13} ).

Step-by-step explanation:

Given the linear equation in standard form, 12x + 13y = 8:

We must transform this equation into slope-intercept form to make it easier to determine the coordinates of the y-intercept.

12x + 13y = 8

Subtract 12x from both sides:

12x + 13y - 12x = - 12x + 8

13y = - 12x + 8

Next, divide both sides of the equation by 13 to solve for y:

\frac{13y}{13} = \frac{-12x + 8}{13}

y = \frac{-12x + 8}{13} or  y = -\frac{12}{13} x + \frac{8}{13}

Next, to determine the y-intercept, we must set x = 0 (because the y-intercept is  the point where the graph of the linear equation crosses the y-axis).

Let x = 0:

y = -\frac{12}{13} x + \frac{8}{13}

y = -\frac{12}{13} (0) + \frac{8}{13}

y = \frac{8}{13}

Therefore, the value of y when x = 0 is \frac{8}{13} . This is the y-intercept, and its coordinate is (0,  \frac{8}{13} ).

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