Question

What are the coordinates of the y-intercept of the line who's equation is 12x + 13y =8???

Answer 1

Answer:

y-intercept = (0,  $\frac{8}{13}$ ).

Step-by-step explanation:

Given the linear equation in standard form, 12x + 13y = 8:

We must transform this equation into slope-intercept form to make it easier to determine the coordinates of the y-intercept.

12x + 13y = 8

Subtract 12x from both sides:

12x + 13y - 12x = - 12x + 8

13y = - 12x + 8

Next, divide both sides of the equation by 13 to solve for y:

$\frac{13y}{13} = \frac{-12x + 8}{13}$

$y = \frac{-12x + 8}{13}$ or  $y = -\frac{12}{13} x + \frac{8}{13}$

Next, to determine the y-intercept, we must set x = 0 (because the y-intercept is  the point where the graph of the linear equation crosses the y-axis).

Let x = 0:

$y = -\frac{12}{13} x + \frac{8}{13}$

$y = -\frac{12}{13} (0) + \frac{8}{13}$

$y = \frac{8}{13}$

Therefore, the value of y when x = 0 is $\frac{8}{13}$ . This is the y-intercept, and its coordinate is (0,  $\frac{8}{13}$ ).