If the equation is passing trough the origin, it will be passing trough the point (0,0). We now for our problem that the equations is also passing trough the point (-4,3). So, our line is passing trough the points (0,0) and (-4,3). To write the equation in slope-intercept form, first, we need to find its slope

. To do that we are going to use the slope formula:

.
From our two points we can infer that

,

,

,

. Lets replace those values in the slope formula:




Now that we have our slope, we can use the slope-intercept formula:



We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is

.
Tienes la tarea en Ingles? Yo solo puedo hacer mathematics en ingles. Gracias.
Answer:
(x + 2) • (x - 19)
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 1 • -38 = -38
Step-2 : Find two factors of -38 whose sum equals the coefficient of the middle term, which is -17 .
-38 + 1 = -37
-19 + 2 = -17 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -19 and 2
x2 - 19x + 2x - 38
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-19)
Add up the last 2 terms, pulling out common factors :
2 • (x-19)
Step-5 : Add up the four terms of step 4 :
(x+2) • (x-19)
Which is the desired factorization
Answer:
(h o g)(-1)) = 50
Step-by-step explanation:
Here, the functions are defined as
g(x) = 5x -2

Now, (h 0 g) (x) is defined as the function h of g(x).
⇒ (h 0 g) (x) = h(g(x))
now, by definition of both functions:
h(g(x)) = h(5x-2) = 
⇒
Putting x = -1 in the above expression,

Hence, h(g(-1)) = 50 or
(h o g)(-1)) = 50