Question

HELP!! let g(x)=5x-2 and h(x)= x^2 +1. Find (h o g) (-1)

Answer 1

Answer:

(h o g)(-1))  = 50

Step-by-step explanation:

Here, the functions are defined as

g(x) = 5x -2

$h(x) = x^{2} + 1$

Now, (h 0 g) (x) is defined as the function h of g(x).

⇒  (h 0 g) (x) = h(g(x))

now, by definition of both functions:

h(g(x))  = h(5x-2)  = $(5x-2)^{2} + 1$

⇒$h(g(x)) = (25x^{2} + 4 - 20x)+ 1 = 25x^{2} + 5 - 20x$

Putting x = -1 in the above expression,

$h(g(-1)) = 25(-1)^{2} + 5 - 20(-1)\\= 25 + 5 + 20= 50$

Hence, h(g(-1))  = 50 or

(h o g)(-1))  = 50