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Inessa05 [86]
3 years ago
10

5+17 HURRY I REALLY NEED TO NO

Mathematics
2 answers:
Yanka [14]3 years ago
6 0

5 + 17 = 22
Tems11 [23]3 years ago
3 0

The answer is 22......

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Find the volume of the figure above. Round to the nearest tenth.
Alina [70]

Answer:

1796.6 m³

Step-by-step explanation:

area of base = 1/2(11 + 16) x 9.5 = 128.33 m²

128.33(14) = 1796.6 m³

5 0
3 years ago
PLEASE HELP WITH THIS PLEASE
olchik [2.2K]
The answer is X-2
The third answer
7 0
3 years ago
Read 2 more answers
A golf association sets performance standards for golf balls. For​ example, the initial velocity of the ball may not exceed 250
Oksanka [162]

Answer:

In this context 38% represents that if the mean speed of ball is 250 ft/sec, then there is 34% chance of obtaining a similar or more extreme value related to test statistics.

Step-by-step explanation:

We are given that the initial velocity of the ball may not exceed 250 feet per second when measured by an apparatus approved by the association.

Based on the mean speed in the​ sample, the association comes up with a​ P-value of 0.38.

Let \mu = <u><em>mean speed of the ball</em></u>

So, Null Hypothesis, H_0 : \mu = 250 ​ft/sec

Alternate Hypothesis, H_A : \mu > 250 ft/sec

Now, the P-value given to us is 0.38.

P-value basically tells us the exact percentage where our test statistics lie. Also, it is the probability of obtaining the value that is more extreme, given that null hypothesis is true,

So, in this context 38% represents that if the mean speed of ball is 250 ft/sec, then there is 34% chance of obtaining a similar or more extreme value related to test statistics.

7 0
4 years ago
1. Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1,
lord [1]

Answer:

To check all the events (6), we label the chips. Suppose one chip with 1 is labeled R1 and the other B1 (as if they were red and blue). Now, lets take all combinations; for the first chip, we have 4 choices and for the 2nd chip we have 3 remaining choices. Thus there are 12 combinations. Since we dont care about the order, there are only 6 combinations since for example R1, 3 is the same as 3, R1 for us.

The combinations are: (R1, B1), (R1, 3), (R1, 5), (B1, 3), (B1, 5), (3,5)

We have that in 1 out of the 6 events, Miguel wins 2$ and in five out of the 6 events, he loses one. The expected value of this bet is: 1/6*2+5/6*(-1)=-3/6=-0.5$. In general, the expected value of the bet is the sum of taking the probabilities of the outcome multiplied by the outcome; here, there is a 1/6 probability of getting the same 2 chips and so on. On average, Miguel loses half a dollar every time he plays.

please mark me brainliest :)

5 0
4 years ago
(15-4i)(6-3i) = a +bi
kati45 [8]

The real part of the result is the product of the real parts of the factors and the product of the imaginary parts:

a = 15*6 - (-4)(-3) = 90 -12 = 78

_____

You can treat this the same as any other product of binomials except that i² = -1.

... (15 -4i)(6 -3i) = 15(6 -3i) -4i(6 -3i) = 15·6 -15·3i -4·6i +4·3i²

... = 90 -45i -24i +12i² = (90 -12) -69i = 78 -69i

7 0
4 years ago
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