Answer:
(3X -8) (X +2)
=(3X^2 + 6X - 8X -16)
use the quadratic formula
a=3
b=-2
c=-16
therefore your x=8/3 or -2
In order to satisfy the requirement, this are the following that is required;First, at least one observation must be above or below 90 seconds. Second is ether the population is normally distributted or greater than (>) 30, or maybe both.
The answer in this question is A and B.
Answer:
- Let p be the population at t be the number of years since 2011. Then,

- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then, 
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get

Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get

Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students
Answer:
Here you go! I have a graph for your answer!
Step-by-step explanation:
The Xmin is -10
The Xmax is 10
The Ymin is -10
Ans the Ymax is 10
Answer:
9 - b = ? 9 - 8 = 1 So, your answer is 1.
Step-by-step explanation: