The volume of a sphere, V = (4/3)(PI)(R^3)
Let k = (4/3)(PI)
Therefore, V = k (R^3)
Let R’ = new radius = 2R
V’ =k (R’^3)
= k (2R)^3
= 8 k R^3
= 8 V
The volume would be eight time the original volume.
The solution to the system of equations is x = 3 and y = 10
<h3>How to solve the equations?</h3>
The system is given as:
2x-2y=-14
3x-y=-1
Multiply (1) by 1 and (2) by 2
So, we have:
1(2x-2y=-14)
2(3x-y=-1 )
This gives
2x - 2y=-14
6x - 2y=-2
Subtract the equations
-4x = -12
Divide by -4
x = 3
Substitute x = 3 in 3x-y=-1
3(3)-y=-1
Evaluate
9 - y = -1
Solve for y
y = 10
Hence, the solution to the system of equations is x = 3 and y = 10
Read more about system of equations at:
brainly.com/question/12895249
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Step-by-step explanation:
∫₀³⁰ (r/V C₀ e^(-rt/V)) dt
If u = -rt/V, then du = -r/V dt.
∫ -C₀ e^u du
-C₀ ∫ e^u du
-C₀ e^u + C
-C₀ e^(-rt/V) + C
Evaluate between t=0 and t=30.
-C₀ e^(-30r/V) − -C₀ e^(-0r/V)
-C₀ e^(-30r/V) + C₀
C₀ (-e^(-30r/V) + 1)
I got the same answer. Try changing the lowercase v to an uppercase V.
Plz help ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
Deffense [45]
Hi I figured it out for you all you need to do is plug in the X factor .number 3 is y=-1
For us to find out how many times more expensive is the deli roast compared to the uncooked roast we need to change the units;
cost of 100g=0.221lb is $2.99
cost of 1 lb will therefore be:
1/0.221*2.99
=$13.53/lb
therefore the number of times more expensive the deli roast is compared to uncooked roast is:
[price of 1lb roasted meat]/[price of 1 lb uncooked meat]
=13.53/4.99
=2.7 times
