When (x+2)to the 6th power is written as polynomial

1 answer:

3 0

(x+2)^6
=(x^2+4x+4)(x+2)^5
=(x^3+6x^2+12x+8)(x+2)^4
=(x^4+6x^3+24x^2+32x+16)(x+2)^3
=(x^5+8x^4+36x^3+80x^2+80x+32)(x+2)^2
=(x^6+10x^5+52x^4+152x^3+240x^2+192x+64)(x+2)
=x^7+12x^6+72x^5+254x^4+544x^3+472x^2+448x+164

Answer: x^7+12x^6+72x^5+254x^4+544x^3+472x^2+448x+164

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How do i resolve this?

EleoNora [17]

Solve for y for both equations then equate and solve:

5x + 9y = 160
9y = 160 - 5x
y = 160/9 - 5/9x

9x + 8y = 202
8y = 202 - 9x
y = 202/8 - 9/8x

160/9 - 5/9x = 202/8 - 9/8x (common denominator is 72)

1280/72 - 40/72x = 1818/72 - 81/72x
1818/72 - 1280/72 = 81/72x - 40/72x
538/72 = 41/72x
538 = 41x
538/41 = x
x = 13 5/41

3 0

3 years ago

At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t

grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

Step-by-step explanation:

Let X = temperature increase.

The random variable X follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of X is:

$f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.$

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

$P(X$

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

$P(20$

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

$P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467$