Answer:
There is only one distinct triangle possible, with m∠N ≈ 33°. i hope this helps :)
Step-by-step explanation:
In △MNO, m = 20, n = 14, and m∠M = 51°. How many distinct triangles can be formed given these measurements?
There are no triangles possible.
There is only one distinct triangle possible, with m∠N ≈ 33°.
There is only one distinct triangle possible, with m∠N ≈ 147°.
There are two distinct triangles possible, with m∠N ≈ 33° or m∠N ≈ 147°.
Answer:
Step-by-step explanation:
44 = 2 * 2 * 11
= 2² *11
Answer:
0.125 and 1/8
Step-by-step explanation:
To convert a percentage to a decimal, divide by 100 to move 2 decimal places to the left.
12.50% / 100 = 0.125
To convert a percentage into a fraction, rewrite the decimal number you got and put it over 1. Multiply the numerator and denominator by 1000 to move 3 decimal places to the right and get your fraction.
·
= 125/1000
Divide the numerator and denominator by the GCF, 125, to get your simplified fraction.
125/125 = 1
1000/125 = 8
125/1000 = 1/8
<span>So, "2.5 more than the quotient of h and 3 is w" becomes 2.5 + h/3 = w. </span>
Answer:

Step-by-step explanation:
<em>Given:</em>
Mn is diameter of circle having centre O
and BD = OD,
<em><u>To prove that:</u></em>
<u>
</u>
<em>Solution:</em>
Join the points O and B and draw OB,
On joining the line,
in ∆OCD and ∆OBD,
OC =OB → (Radius of same circle)
BD =CD → (from given)
OD =OD → (Common side in both the triangles)
Hence ∆OCD and ∆OBD are congruent from SSS property.
so we can say that,

Consider above prove as statement A
Corresponding angles of congruent traingle.
in ∆ OAB,
OA = OB (radius of same circle)
hence ∆OAB is an isosceles traingle.
We know that opposite angle of isosceles traingle are always equal. hence,

Consider above prove as statement B
From Statement A & B we can say that

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