<span>The object's speed is 8/5 miles per hour or 1.6 mph.</span>
3.48 x 10^ -5
move the decimal point back to the first number that isn't zero, if the decimal is moved right 5 spaces, it will be 10^ -5 , if a number has a zero, such as 0.000104, it would be 1.04 x 10^ -4.
Answer:
A quadratic equation can be written as:
a*x^2 + b*x + c = 0.
where a, b and c are real numbers.
The solutions of this equation can be found by the equation:

Where the determinant is D = b^2 - 4*a*c.
Now, if D>0
we have the square root of a positive number, which will be equal to a real number.
√D = R
then the solutions are:

Where each sign of R is a different solution for the equation.
If D< 0, we have the square root of a negative number, then we have a complex component:
√D = i*R

We have two complex solutions.
If D = 0
√0 = 0
then:

We have only one real solution (or two equal solutions, depending on how you see it)
Answer:
public class MovieRental
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Enter the number of movie rentals: ");
int movieRentals = in.nextInt();
System.out.print("Enter the number of members referred to the video club: ");
int memberReferral = in.nextInt();
in.close();
double discountVal = Math.min(movieRentals + memberReferral, 75);
System.out.println("The discount is equal to: " + discountVal);
}
}