The sum of 3 consecutive odd #s is 51 what are the 3#s?
2 answers:
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Answer:
10-5
Step-by-step explanation:
As per the attached figure, right angled has an inscribed circle whose center is
.
We have joined the incenter to the vertices of the
.
Sides MD and DL are equal because we are given that
Formula for <em>area</em> of a
As per the figure attached, we are given that side <em>a = 10.</em>
Using pythagoras theorem, we can easily calculate that side ML = 10
Points P,Q and R are at on the sides ML, MD and DL respectively so IQ, IR and IP are heights of
MIL,
MID and
DIL.
Also,
So, radius of circle =
Answer:
0 ≤ Ф ≤ 4π.
Step-by-step explanation:
since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))
the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.
We take
Note that
Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.
The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.
Answer:
Step-by-step explanation:
Answer:
a) 10.75% probability that exactly 30 of them will pass the quality control checks.
b) Expected value is 32
Variance is 6.4
Step-by-step explanation:
For each monitor, there are only two possible outcomes. Either they will pass the quality checks, or they will not pass these checks. The probability of a monitor passing these checks is independent of other monitors. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The expected value of the binomial distribution is:
The variance of the binomial distribution is:
80% of the monitors made by your company will pass your stringent quality control checks.
This means that
40 monitors have just come off the assembly line.
This means that
a) What is the probability that exactly 30 of them will pass the quality control checks?
This is P(X = 30). So
10.75% probability that exactly 30 of them will pass the quality control checks.
b) What are the expected value and variance of the number of these monitors that will pass the quality control checks?
Expected value is 32
Variance is 6.4