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3 years ago

How do i solve f(x)=|x-2|+3

Mathematics

1 answer:

Olenka [21]3 years ago

7 0

Answer:

f(x)=|x-2|+3

0=|x-2|+3

0-3=|x-2|+3-3

-3+2=x-2+2

-1=x

Step-by-step explanation:

set the function equal to zero
you can subtract 3 from both sides or you can add -2 and 3 and then you subtract your answer from both sides to solve for x

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3 years ago

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Answer:

$\huge{ \fbox{ \sf{ \: ( \: 3 \: , \: - 1 \: )}}}$

Step-by-step explanation:

$\star{ \sf { \: Let \: the \: points \:be \: A \: and \: B}}$

$\star{ \sf{ \: Let \: \: A (8,6) \: be \: (x1 \:, y1) and \: B(-2,-8) \: be \: (x2 \:, y2)}}$

$\underline{ \sf{Finding \: the \: midpoint}}$

$\boxed{ \rm{Midpoint \: = \: ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

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$\mapsto{ \sf{Midpoint = (3 \: \: , - 1)}}$

Hope I helped!

Best wishes!! :D

~ $\sf{TheAnimeGirl}$

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