How to dilate exponential functions

Mathematics

1 answer:

allsm [11]2 years ago

7 0

I don’t know how to explain it so here’s a link that I used back when we learned this stuff;

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What is the binomial

mina [271]

Answer:

Step-by-step explanation:

The coefficients of the expansion of (a + b)^2 are 1 2 1, which is the third row of Pascal's triangle.

For (a + b)^3 they are 1 3 3 1 which is in the 4th row, and so on

So those for the (a + b)^n are in the (n + 1)th row.

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3 years ago

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Find the equation of the line thatcpasses through (3, 1) and is parallel to y=1-2x.

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Slope of y=1-2x is -2
Using point intercept form:
y-1=-2(x-3)
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2 years ago

how do theme and tone work together? a. theme involves characters, and tone involves the historical context of those characters.

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3 years ago

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$