Simplify the variable expression by evaluating its numerical parts and enter your answer m - 22 + 37

xenn [34]

$\dfrac{3}{4} = \dfrac{3 \times 3}{4 \times 3} = \dfrac{9}{12}$

$\dfrac{4}{6} = \dfrac{4 \times 2}{6 \times 2} = \dfrac{8}{12}$

$\dfrac{9}{12} \ \textgreater \ \dfrac{8}{12}$

$\dfrac{3}{4} \ \textgreater \ \dfrac{4}{6}$

7 0

3 years ago

David swan, biked, and ran in the Camp Race. She biked twice as long as she ran, and swam 15 minutes more than she ran. Her tota

lidiya [134]

Answer:

She biked 40 minutes.She ran 20 minutes.She swam 35 min.

Step-by-step explanation:

since you have 95 minutes for all parts first subtracted 15 from what she swam the you have four equal parts left the time she ram then twice she ran she biked and then the she swam 15 minutes More that she ran so you dived 95-15 which is 80 80/4 is 20 so she ran 20 min so 20 x 2 is 40 for she bike 40 then 20+15 is 35 so 40+20+35=95 an hour an 35 minutes

6 0

3 years ago

Which is the graph of f(x) = x2 – 2x + 3?

BaLLatris [955]

Answer:

Step-by-step explanation:

We cannot factor this function out which tells us that there are no zeros. The graph backs this up because we can see that there are none. The easiest way to graph this would start by plugging in points and making a table for yourself.

Lets start by plugging in -1.

(-1)^2-2(-1)+3 =6, this means we have a point at (-1,6).

Now lets plug in 0.

(0)^2-2(0)+3= 3 (0,3)

For plugging in 1

(1)^2-2(1)+3=2 (1,2) (this happens to be the vertex)

And lastly lets plug in 2

(2)^2-2(2)+3=3 (2,3)

Depending on how many points are needed, keep plugging in numbers like we did above.

7 0

3 years ago

On a trip, Duke encounters some road construction that slows him down. While he is able to go 60 mph on the highway and 40 mph t

natulia [17]

Answer:

Time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

Step-by-step explanation:

Speed by which Duke travels a distance on highway $d_1$ = 60 mph

Let the time taken to travel on highway = $t_1$ hours

Distance traveled = $60t_1$ miles

Speed in the city = 40 mph

Let the time taken = $t_2$ hours

Distance traveled in the city = $40t_2$ miles

Speed on the construction = 20 mph

Let the time spend on the construction = $t_3$ hours

Distance traveled on the construction = $20t_3$ miles

Since, total distance covered = 380 miles

$d_1+d_2+d_3=60t_1+40t_2+20t_3$

He spends one half the time on the highway as he does on the construction,

$t_3=2t_1$

Total time spent in the trip = 11 hours

Therefore, $t_1+t_2+t_3=11$

$t_1+t_2+2t_1=11$

$t_2=11-3t_1$

From equation (1),

$60t_1+40(11-3t_1)+20(2t_1)=380$

$60t_1-120t_1+40t_1+440=380$

$440-20t_1=380$

$20t_1=440-380$

$t_1=\frac{60}{20}$

$t_1=3$ hours

$t_2=11-3t_1=2$ hours

$t_3=2t_1=6$ hours

Therefore, time taken by Duke on the highway = 3 hours

Time spent on the construction = 6 hours

Time spent in the city = 2 hours

3 0

3 years ago

Please help as soon as possible 50 points

Morgarella [4.7K]

Answer:

the answer is d. 4x²+x-6

Step-by-step explanation:

In order to combine the fractions, they need to have the same denominator.

So, multiply each of their numerators by the denominator they need to be equivalent.

This would look like this:

3x/x+3 --> 3x(x)/x(x+3) ---simplify this as--> 3x²/x(x+3)

x-2/x --> (x-2)(x+3)/x(x+3) ---simplify this as --> x²+x - 6/x(x+3)

3x 3x(x) x-2 (x-2)(x+3)

----- ---> ----- and -------- ---> ---------

x+3 x(x+3) x x(x+3)

now that both fractions have the same denominator, we can add their numerators.

3x² + x²+x-6 = 4x²+x -6

This should now look like this:

4x²+x -6

-------------

x(x+3)

8 0

2 years ago

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Simplify the variable expression by evaluating its numerical parts and enter your answer m - 22 + 37 - 8