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nadya68 [22]
3 years ago
11

Help me! Lots of points! Put these numbers in order from least to greatest:

7B20%7D%20%5C%5C4.84%20%2A%2010%5E%7B19%7D%20%5C%5C4.9%20%2A%2010%5E%7B19%7D" id="TexFormula1" title="4.35 * 10^{20} \\4.84 * 10^{19} \\4.9 * 10^{19}" alt="4.35 * 10^{20} \\4.84 * 10^{19} \\4.9 * 10^{19}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
julia-pushkina [17]3 years ago
7 0

Lets turn each number into standard form.

4.35 * 10^20 = 435,000,000,000,000,000,000

4.84 * 10^19 = 48,400,000,000,000,000,000

4.9 * 10^19 = 49,000,000,000,000,000,000

4.84 * 10^19 < 4.9 * 10^19 < 4.35 * 10^20

Therefore, the numbers from least to greatest is 4.84 * 10^19, 4.9 * 10^19, and 4.35 * 10^20

Best of Luck!

aleksandrvk [35]3 years ago
6 0

Answer:

4.84 × 10¹⁹

4.9 × 10¹⁹

4.35 × 10²⁰

Step-by-step explanation:

4.35 × 10²⁰ = 43.5 × 10¹⁹

4.84 × 10¹⁹

4.9 × 10¹⁹

Order is:

4.84 × 10¹⁹

4.9 × 10¹⁹

4.35 × 10²⁰

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When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select and test 55 bat
aleksley [76]

The probability of accepting this shipment is 98%.

What is probability?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Here, we have

Almost all such shipments will be accepted because the probability of having a sample with more than 3 defective batteries is very low.

The shipment will be accepted if at most 3 batteries don't meet specifications.

This can be modeled as a binomial distribution, where the sample size is n=55 and the probability of not meeting the specifications of any battery is p=0.02.

The shipment will be accepted if D ≤ 3.

The probability of this event is:

P( D ≤ 3) = P(D=0) + P(D=1) + P(D=2) + P(D=3)

P(D=X) = n!/(x!(n-x)!) pˣ(1-p)ⁿ⁻ˣ

P(D=0) = 55!/(0!(55-0)!) 0.02⁰(1-0.02)⁵⁵⁻⁰ = 1× 1 × 0.32 = 0.32

P(D=1) = 55!/(1!(55-1)!) 0.02¹(1-0.02)⁵⁴ = 54 × 0.02 × 0.33= 0.35

P(D=2) = 55!/(2!(55-2)!) 0.02²(1-0.02)⁵³ = 55 ×27 × 0.0004 × 0.34= 0.20

P(D=3) = 55!/(3!(55-3)!) 0.02³(1-0.02)⁵² = 25740× 0.0000008 × 0.35= 0.07

Then,

P( D ≤ 3) = P(D=0) + P(D=1) + P(D=2) + P(D=3)

P( D ≤ 3) = 0.32 + 0.35 + 0.20 + 0.07

P( D ≤ 3) = 0.98

Hence, the probability of accepting this shipment is 98%.

To learn more about the probability from the given link

brainly.com/question/24756209

#SPJ1

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