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TEA [102]
3 years ago
9

Which of the following expressions are equivalent to - -a/b

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0

Answer:

B) -\frac{a}{-b}

Step-by-step explanation:

1. First, we have to know that two negatives equal positive.

2. Given the information above, -\frac{-a}{b} can simplify to \frac{a}{b}.

3. Let's go through each answer choice and see which one also simplifies to \frac{a}{b}.

A:

  • \frac{a}{-b}
  • -\frac{a}{b}

B:

  • -\frac{a}{-b}  
  • \frac{a}{b}

Therefore, the answer is B) -\frac{a}{-b}.

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Please help me check my work and correct me if I'm wrong.
Aleonysh [2.5K]
I believe you are right with all of them.
7 0
3 years ago
Read 2 more answers
How would the expression x^2-4 be rewritten using Difference of Squares?
Anna [14]
<span>a2 – b2 = (a + b)(a – b) or (a – b)(a + b).
This is the 'Difference of Squares' formula we can use to factor the expression.

In order to use the </span><span>'Difference of Squares' formula to factor a binomial, the binomial must contain two perfect squares that are separated by a subtraction symbol.

</span><span>x^2 - 4 fits this, because x^2 and 4 are both perfect squares, and they are separated by a subtraction symbol.
All you do here to factor, is take the square root of each term.

√x^2 = x
√4 = 2

Now that we have our square roots, x and 2, we substitute these numbers into the form (a + b)(a - b).
</span>
<span>(a + b)(a - b)
(x + 2)(x - 2)

Our answer is final </span><span>(x + 2)(x - 2), which can also be written as (x - 2)(x + 2), it doesn't make a difference which order you put it in.

Anyway, Hope this helps!!
Let me know if you need help understanding anything and I'll try to explain as best I can.</span>
3 0
3 years ago
Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?
Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

\sin^2 \theta +\cos^2 \theta = 1

Let us solve this equation for cosine function.

\cos^2 \theta = 1-\sin^2 \theta

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

\cos \theta=\sqrt{1-\sin^2 \theta}

Thus, the correct option is: True; quadrants I & IV


6 0
4 years ago
Read 2 more answers
WORTH A WHOLE LOTTA POINTS!
dangina [55]

Where did you get that A and B? I could answer if you were much more precise.

8 0
4 years ago
Simplify
Fantom [35]
2+5=7
7-3=4
so the answer is b 
6 0
3 years ago
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