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Darina [25.2K]
3 years ago
5

Select the correct statement about cellular respiration.

Biology
1 answer:
weeeeeb [17]3 years ago
6 0

I dont want to mislead you, but I believe the answer is A because letter B is wrong because plants go through cellular respiration and photosynthesis, whereas animals go through cellular respiration but not photosynthesis, and for C, I've never heard of that so it doesnt seem likely.

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What role does cellular respiration play in the carbon cycle?
Liono4ka [1.6K]
During cellular respiration, carbon dioxide is released to the atmosphere during the formation of acetyl coenzyme A<span>. This step involves the oxidative decarboxylation of pyruvic acid, the result of which is carbon dioxide. This carbon dioxide is uptaken by plants and used in the process of photosynthesis to produce glucose.</span>
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3 years ago
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A geologist is studying two different rhyolite flows to determine if they were erupted at the same time.
ss7ja [257]
Q1. The answer is 1.

It can be calculated using the equation:

 (1/2)ⁿ = x

x - decimal amount remaining, 

n - a number of half-lives.


x = 50% = 50/100 = 0.5

n = ?

(1/2)ⁿ = 0.5

log((1/2)ⁿ) = log(0.5)

n * log(1/2) = log(0.5)

n * log(0.5) = log(0.5)

n = log(0.5)/log(0.5)

n = 1


Q10. The answer is 2.


It can be calculated using the equation:

 (1/2)ⁿ = x

x - decimal amount remaining, 

n - a number of half-lives.


Rhyolite #2 has 25% of the parent H remaining:

x = 25% = 25/100 = 0.25

n = ?

(1/2)ⁿ = 0.25

log((1/2)ⁿ) = log(0.25)

n * log(1/2) = log(0.25)

n * log(0.5) = log(0.25)

n = log(0.25)/log(0.5)

n = -0.602 / - 0.301

n = 2



Q3. The answer is 100 million years.


A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):

n = t/H

n = 1

t = ?

H = 100 000 000 years


n = t/H

t = n * H

t = 1 * 100 000 000 years

t = 100 000 000 years<span>

</span>

4 0
3 years ago
If anyone is willing to help me, I will greatly appreciate it. I can’t afford to fail… I need to graduate so I can achieve my go
Valentin [98]

Answer:

1) you're going to have to flip the coins (or fake numbers) for the experimental trials.

2) for the theoretical, there is 1/2 chance for heads or tails with each toss, so you'd expect that out of 10 tosses, 5 heads, 5 tails. out of 100 tosses- 50 heads, 50 tails.

When tossing 2 coins- 1/2×1/2 = 1/4 (25%) chance that 2 heads, 2 tails, or 1 heads & 1 tails. Deviation value comes from after you done your flipping and recorded your data. So if on 100 flips you actually got 50 and 50 (rarely us that exact ;), the deviation from the expected of 50/50 would be 0.00. If however you flipped 100 heads or 100 tails (impossible), then the deviation value would be 1.00.

|(100-50)| ÷ 50 = 50÷50 = 1.00

So usually you may have data like: 47/53 or something a little off than 50/50, making deviation |(47-50)| ÷ 50 = 3÷50 = 0.06.

Now the number of flips is important for the outcome! So if a coin toss if 10 times had 4 heads, 6 tails, the deviation value would be:

|(4-5)| ÷ 5 = 1÷5 = 0.20

So increasing the # flips DECREASES the deviation value!!

Whether it's from 10 to 100, or from 100 to 200. Look at my example of how the 10-flip deviation of 0.20 decreased to 0.06 with 100-flip

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As the temperature of a star is increased, what happens to the wavelength?
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The wavelengths gets bigger
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