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3 years ago

Write these values in order, starting with the smallest. 0.2 1/2 2%

Mathematics

1 answer:

katen-ka-za [31]3 years ago

5 0

Step-by-step explanation:

In this case we need to arrange the given number in a order starting with the smallest.

First number is 0.2

Second number is 1/2

Third number is 2%

Firstly, we need to convert these number in same form i.e. decimal form.

1/2 can be written as 0.5

2% can be written as $\dfrac{2}{100}=0.02$

Now, it is required to arrange these number from smallest to largest. So,

0.02 is the smallest number and 0.5 is the largest number.

Order is : 0.02, 0.2, 0.5

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Please help me with this problem thank you

horsena [70]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A right cone has a radius of 13 cm and a slant height of 20 cm. Find its surface area.

devlian [24]

Answer:

$A=1347.7\ cm^2$

Step-by-step explanation:

Given that,

Radius of a cone, r = 13 cm

Slant height of the cone, l = 20 cm

We need to find the surface area of the cone. The formula for the surface area of the cone is given by :

$A=\pi rl +\pi r^2$

Put all the values,

$A=\pi r(l + r)\\\\A=\pi \times 13(20 + 13)\\\\A=1347.7\ cm^2$

So, the surface area of the cone is $1347.7\ cm^2$ .

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2 years ago

If R is the midpoint of PS with PR = 7x + 23 and RS= 13x-19 then find PS

Rainbow [258]

If R is the midpoint of PS, then PR = RS -- (1)

Also, PR + RS = PS -- (2)

__________________

PR + RS = PS

7x + 23 + 13x - 19 = PS

__________________

Now, PR = PS

7x + 23 = 13x - 19

7x - 13x = -19 - 23

-6x = -42

x = -42/-6

x = 7

__________________

PS = 7x + 23 + 13x - 19

PS = 7(7) + 23 + 13(7) - 19

PS = 49 + 23 + 91 - 19

PS = 144 

Hope it helps!

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

7 0

2 years ago

Two corresponding sides of similar triangles are 2 cm and 5 cm. What is the area of the second triangle if the area of the first

Stella [2.4K]

Answer:

(1) Area of second triangle= 50 cm^2.

(2) Area of ΔABC=98 cm^2.

and Area of ΔDFG=175 cm^2.

Step-by-step explanation:

" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".

i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

$\dfrac{a^2}{b^2}=\dfrac{A}{B}$

(1)

for the first question:

we have a=2, b=5.

A=8 cm^2.

Hence,

$\dfrac{2^2}{5^2}=\dfrac{8}{B}\\\\\dfrac{4}{25}=\dfrac{8}{B}$

B=50 cm^2.

Hence, the area of second triangle is 50 cm^2.

(2)

In second option we have:

a=6 and b=5.

A-B=77 cm^2.

A=77+B

$\dfrac{6^2}{5^2}=\dfrac{A}{B}\\ \\\dfrac{36}{25}=\dfrac{77+B}{B}\\ \\36B=25\times77+25B\\\\36B-25B=25\times77\\\\11B=25\times77\\\\B=25\times7\\\\B=175$

Hence area of second triangle i.e. ΔDFG is 175 cm^2.

and area of first triangle i.e. ΔABC=175-77=98 cm^2.

8 0

2 years ago

Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

5 0

2 years ago