Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
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Answer: -51 my friend
Step-by-step explanation:
Answer:
n =22
Step-by-step explanation:
12-5=7
15-5=10
20-5=15
n-5=17
collect like terms
n=17+5
n=22
3y-20+x+13=3x+9
3y-20+x+13+2y=180
3y-7+x=3x+9
3y=2x+16
y=2/3x+16/3
5y+x=187
5(2/3x+16/3)+x=187
10/3x+80/3+x=187
13/3x=481/3
x=37