For this case we must find the solution of the following quadratic equation:
Where:
Then, the solution is given by:
Substituting the values:
By definition we have:
Thus, we have two complex roots.
Answer:
The equation has no real roots.
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:
A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?
You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked
2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.
b - 1,000,000/2500 = 400
400 packages are defective each year
Sorry, maybe is too late for you, But the answer is:
For example: 4 x 4=16cm² if <span> one pair of opposite sides was made 50% longer and the other pair of opposite sides was made 50% shorter
It became: 6 x 2=12cm</span>²
12/16=0.75
So, the 75% <span>of the square’s area is the area of the new rectangle.</span>
FW = PW(1+i)^N
= $6900(1+0.039)^1
solve for FW
(sorry don't have a calculator on me rn)
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
<span> x^2-14*x+31-(63)=0 </span><span>x = 16
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