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lara [203]
3 years ago
12

Solve sin x + 2 sin x cos X = for 0°

Mathematics
1 answer:
solniwko [45]3 years ago
3 0

Answer:

Step-by-step explanation:

hello :

sin x + 2 sin x cosx = 0   equivalent to : sinx(1+2cosx) =0

sinx=0 means :  general solution is  : x= kπ....k in Z

1+2cosx=0  means : cosx= -1/2 general solution is : x= ±π/6+kπ...k in Z

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Answer:

The equation is correct

Step-by-step explanation:

The equation, written as:

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Consider the change of base formula:

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Applying the change of base formula to change the expressions in base 2 and base 4 to base 10.

(1)

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(2)

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Now putting the values of these new logs in base 10 into the left-hand side of original equation to verify if we have 3, we have:

[log_10 (2)][log_8 (4)][log_10 (4)]

= [1/ log_10 (2)][log_10 (8) / log_10 (4)][log_10 (4)]

= [1/log_10 (2)] [log_10 (8)]

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= [log_10 (2³)]/[log_10 (2)]

Since log_b (a^x) = xlog_b (a)

= 3[log_10 (2)]/[log_10 (2)]

= 3 as required

Therefore, the left hand side of the equation is equal to the right hand side of the equation.

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