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3 years ago

A box contains 3 defective batteries and 7 good ones. You reach in and pull out three

Mathematics

1 answer:

fomenos3 years ago

8 0

Answer:

The expected number of defective batteries to be pulled out is 0.9, which rounded to the nearest integer gives a total of 1, that is, 1 of the 3 batteries is expected to be defective.

Step-by-step explanation:

Given that a box contains 3 defective batteries and 7 good ones, and I reach in and pull out three batteries, to determine what is the expected number of defective batteries, the following calculation must be performed:

3 + 7 = 100

3 = X

10 = 100

3 = X

3 x 100/10 = X

300/10 = X

30 = X

3 x 3/10 = X

0.9 = X

Therefore, the expected number of defective batteries to be pulled out is 0.9, which rounded to the nearest integer gives a total of 1, that is, 1 of the 3 batteries is expected to be defective.

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Step-by-step explanation:

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3 years ago

Find the average rate of change of f ( x ) = 3 x 2 − 9 on the interval [ 2 , b ] . Your answer will be an expression involving b

iVinArrow [24]

Answer:

$m = 3b+6$

Step-by-step explanation:

Given

$f(x)=3x^2 - 9$

Required

The average rate over $[2,b]$

Average rate (m) is calculated using:

$m = \frac{f(b) - f(a)}{b - a}$

Where

$[a,b] = [2,b]$

So, we have:

$m = \frac{f(b) - f(2)}{b - 2}$

Calculate f(b) and f(2)

$f(x)=3x^2 - 9$

$f(b)=3b^2 - 9$

$f(2)=3*2^2 - 9 = 12 - 9 = 3$

So, we have:

$m = \frac{f(b) - f(2)}{b - 2}$

$m = \frac{3b^2 - 9 - 3}{b - 2}$

$m = \frac{3b^2 - 12}{b - 2}$

Expand the numerator

$m = \frac{3b^2 + 6b-6b-12}{b - 2}$

Factorize

$m = \frac{b(3b + 6)-2(3b+6)}{b - 2}$

Factor out 3b + 6

$m = \frac{(b -2)(3b+6)}{b - 2}$

Cancel out b - 2

$m = 3b+6$

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3 years ago

Evaluate the following. d/dx(10^x + e^2)

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d/dx[10x+e2]
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3 years ago

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Answer:

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Step-by-step explanation:

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