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fgiga [73]
3 years ago
6

1.2 ÷ 4 = 12 tenths ÷ 4 = 3 tenths =

Mathematics
1 answer:
GarryVolchara [31]3 years ago
8 0

Answer:

uhhh

Step-by-step explanation:

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It took John 4 hours from his home to drive to Leakey, Tx.. On the way home his speed was reduced by 20 MPH due to heavy traffic
Vesna [10]

Let the speed at which John is going towards Leakey = x mph

Time taken to reach Leakey = 4 hours

Distance = speed * time

So let the distance of Leakey from John's house be 4x ............. (1)

Speed while returning was 20 mph less = (x-20)

Time taken was= 7 hours

distance = (x-20)*7  ................(2)

As the distance remains the same, equation 1 = equation 2

4x=7(x-20)

4x=7x-140

3x=140

x=\frac{140}{3}

So, the speed is \frac{140}{3} mph

Distance = 4x

= 4*\frac{140}{3}= 186.667

Hence, the distance of Leakey from John's house is 186.667 miles.




6 0
3 years ago
Roger served 5/8 pound of cracker wich was 2/3 of the entire box what was the weight of the crackers originally in the box
horrorfan [7]
Answer:
original weight of the box = 15 / 16 pounds

Explanation:
Assume that the original amount in the box is x.
We are given that:
5/8 pounds represent 2/3 of the total amount (x).
This can be translated into the following equation:
(2/3) x = 5 / 8

Now, we will solve for x as follows:
(2/3) x = 5 / 8
Multiply both sides by 24 to get rid of the denominators as follows:
(2/3) x * 24 = (5 / 8) * 24
16 x = 15
Divide both sides by 16 to isolate the x as follows:
x = 15 / 16 pounds

Hope this helps :)

8 0
4 years ago
When Judy worked 4 hours and Ben worked 1 hour, their combined pay was $75. When Judy worked 2 hours and Ben worked 6 hours, the
arsen [322]

Answer:

$15

Step-by-step explanation:

let the hourly rate of pay for Ben  = B

let the hourly rate of pay for Judy  = J

Judy worked 4 hours and Ben worked 1 hour, their combined pay was $75;

              4J + B = 75 ----- i

Judy worked 2 hours and Ben worked 6 hours, their combined pay was $120

               2J + 6B  = 120 --- ii

Now, we should solve the expression;

   Multiply equation ii by 2 and equation i by 1;

 

            4J + B = 75 ----- i    x 1  ;    4J + B  = 75          -- iii

            2J + 6B  = 120 --- ii  x 2 ;   4J + 12B  = 240    ---iv

Now,

 equation iv - iii;

                   11B  = 165

                      B  = $15

So, solving for J;

          4J + B = 75

         4J + 15  = 75

          4J  = 75 - 15  = 60

          J  = $15

3 0
3 years ago
I WILL GIVE BRAINLIST IF ALL ANSWERED CORRECTLY
pentagon [3]

Answer:

The length of the track is approximately 51.7 ft

The track has three sides of the square and the distance round a half of a complete circle

Step-by-step explanation:

The given track shape and measurements are;

The shape on the left side of the track  = Square

The shape on the right side of the track  = Half circle

The area of the square on the the left side of the track  = 128 square feet

Therefore, from the area, A, of a square of side length, s, which is s × s, and letting the side length of the square = s, we have;

Area of the square portion of the track = s × s = s² = 128 ft²

Therefore, s = √(128 ft²) = 8·√(2) ft.

Whereby the side length of the square is bounded by the diameter of the half circle, we have;

Length of the diameter of the half circle = s = 8·√(2) ft.

The length of the perimeter of the half circle = π·D/2 = π × 8·√(2)/2 = π × 4·√(2) ≈ 17.77 ft.

The perimeter of the track, which is the length of the track is made up of the three sides of the square opposite to the half circle and the circumference of the half circle.

Therefore;

The length of the track = 3 × 8·√(2) ft + π × 4·√(2) ft. = 4·√2×(π+6) ≈ 51.7 ft

The length of the track ≈ 51.7 ft

Which gives;

The track has three sides of the square and the distance round a half of a complete circle.

4 0
3 years ago
A cell phone company recently noticed a 26% sales decrease in the month of July compared to June. Let n represent June’s sales.
Crank

Answer:

a) y = n – 0.26n

Step-by-step explanation:

a) y = n – 0.26n

7 0
3 years ago
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