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stepladder [879]
2 years ago
7

An isosceles trapazoid has base angles of 45 degrees and bases of lengths 9 and 15. The area of the trapazoid is what

Mathematics
1 answer:
lakkis [162]2 years ago
6 0

Answer:

area of trapazoid= 1/2 × b× h

so = 1/2×9×15

=1/2×135

=67.5cm

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Solve: -6n + 5 &lt; 11<br> Wich graph shows the solution?
tangare [24]

Answer:

The last graph

Step-by-step explanation:

You have to solve for n that is where you get the plot then you have to remember in inequalities if you divide by a negative you have to switch the sign. The inequality is not a less than or equal to or greater than or equal to so the plot would be an open circle. Because we switched the sign it goes down the left side of the graph because of the direction the sign is pointing to.

8 0
2 years ago
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Precal help if you could could you answer both. Me finishing this helps me graduate.
oee [108]

Exercise 1:

The easiest way to compute powers of complex numbers is to write them in the form

z = \rho e^{i\theta} = \rho(\cos(\theta)+i\sin(\theta))

In this form, you have

z^n = \rho^n e^{in\theta} = \rho^n(\cos(n\theta)+i\sin(n\theta))

The magnitude of the number is given by

z=a+bi \implies \rho = \sqrt{a^2+b^2}

So, we have

z=-1+\sqrt{3}i \implies \rho = \sqrt{1+3}=2

As for the angle, we have

z=a+bi \implies \theta = \text{atan2}\dfrac{b}{a}

So, we have

z=-1+\sqrt{3}i \implies \theta = \text{atan2}\left(\dfrac{-\sqrt{3}}{-1}\right) = -\dfrac{2\pi}{3}

Finally,

z=-1-\sqrt{3}i = 2\left(\cos\left( -\dfrac{2\pi}{3}\right) + i\sin\left( -\dfrac{2\pi}{3}\right)\right) \implies z^6 = 2^6\left(\cos\left( -4\pi\right) + i\sin\left(-4\pi\right)\right) = 64

Exercise 2:

You simply have to compute the trigonometric function:

\cos\left(-\dfrac{\pi}{4}\right) = \dfrac{\sqrt{2}}{2},\quad \sin\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}

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7 0
3 years ago
20 more than the product of a number n and five​
PtichkaEL [24]

Answer:

5n + 20

Step-by-step explanation:

4 0
2 years ago
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Dimensions definition
Travka [436]
Marie has a small copy of Rene margrittes famous painting. The Schoolmasters. Her copy has dimensions of 2 inches by 1.5 inches. The scale of her copy is 1 inch:40 cm What is the dimensions of the original painting?


Every 1 inch on her copy is the same as 40 cm on the original. 
You just have to multiply by 40 and convert to centimetres.

2 x 40 = 80
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So the original painting is:
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3 0
3 years ago
According to records in a large hospital, the birth weights of newborns have a symmetric and bell-shaped relative frequency dist
Kamila [148]

Answer:

15.9% of babies are born with birth weight under 6.3 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.8 pounds

Standard Deviation, σ = 0.5

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Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(birth weight under 6.3 pounds)

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P(x < -1) = 0.159 = 15.9\%

15.9% of babies are born with birth weight under 6.3 pounds.

8 0
3 years ago
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