Answer:
The amount invested at 9% is $93000
The amount invested at 10% is $303000
Step-by-step explanation:
Let the amount invested at 9% interest rate be x
And the amount invested at 10% rate be y
Simple Interest from x in a year = 0.09x
Simple Interest from y in a year = 0.1y
But y = 24000 + 3x
And the sun of the interests, 0.09x + 0.1y = 38670
Now we have a simultaneous eqn
y = 24000 + 3x (eqn 1)
0.09x + 0.1y = 38670 (eqn)
Substitute y into eqn 2
0.09x + 0.1(24000 + 3x) = 38670
0.09x + 2400 + 0.3x = 38670
0.39x = 38670 - 2400
x = 36270/0.39 = $93000
y = 24000 + 3x = 24000 + 3 × 93000 = $303000
Answer:
If the graphs of the equations do not intersect (for example, if they are parallel), then there are no solutions that are true for both equations. If the graphs of the equations are the same, then there are an infinite number of solutions that are true for both equations.
Step-by-step explanation:
Answer:
option D
D. x = 5, y = 2
Step-by-step explanation:
Given in the question two equation,
Equation 1
5.3x + y = 28.5
Equation 2
4.2x + 3.1y = 27.2
rearrange equation 1 in terms of y
y = 28.5 - 5.3x
Substitute the value of y in equation 2
<h3>4.2x + 3.1(28.5 - 5.3x) = 27.2</h3>
4.2x + 88.35 - 16.43x = 27.2
4.2x - 16.43x = 27.2 - 88.35
-12.23x = -61.15
x = 61.15/12.23
x = 5
put value of x in any of the equation
<h3>5.3(5) + y = 28.5</h3>
y = 28.5 - 26.5
y = 2