Answer:
2 unit/time²
Step-by-step explanation:
Given the equation:
v(t) =t^2-3t
At interval ; 1, 4
V(1) = 1^2 - 3(1)
V(1) = 1 - 3
V(1) = - 2
At t = 4
V(4) = 4^2 - 3(4)
V(4) = 16 - 12
V(4) = 4
Average acceleration : (final - Initial Velocity) / change in time
Average acceleration = (4 - (-2)) ÷ (4 - 1)
Average acceleration = (4 + 2) / 3
Average acceleration = 6 /3
Average acceleration = 2
Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125
Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50. #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5
Let x=the first number
Then x+7=second number
And 4(x+7)+2=third number (2 more than 4 times the second)
Now we are told that:
x+(x+7)+(4(x+7)+2)=85 get rid of parentheses
x+x+7+4x+28+2=85 simplify
6x+37=85 subtract 37 from each side
6x+37-37=85-37
6x=48
x=8---first number
x+7=8+7=15 second number
4(x+7)+2=4*15+2=62 third number
CK
8+15+62=85
85=85
The answer is 6m - 6 = 8m + 4
Hope this helps please give brainless!!!
Answer: so you do 5+8, then get 13. 13-5=8
Step-by-step explanation: