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Vesna [10]
3 years ago
11

What is an explicit formula for the geometric sequence -64,16,-4,1,... where the first term should be f(1).

Mathematics
1 answer:
nirvana33 [79]3 years ago
7 0

Answer:

a_{n} = -64(-\frac{1}{4})^{n-1}

it seems like the first term is -64, so lets write the formula accordingly:

a_n = a1(r)^(n-1)

where 'n' is the number of terms

a1 is the first term of the sequence

'r' is the ratio

the ratio is -\frac{1}{4} because -64 * -\frac{1}{4} = 16 and so on...

the explicit formula is :

a_{n} = -64(-\frac{1}{4} )^{n-1}

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Allushta [10]

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7 0
3 years ago
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What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?
Nadya [2.5K]
<u>x-intercepts are found by setting y=0</u>
y=2x^2-8x-10\rightarrow0=2x^2-8x-10
<em>factor out a 2</em> 0=2(x^2-4x-5)\rightarrow0=x^2-4x-5
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therefore, x-intercepts are (-1,0) and (5,0)
<u>
</u><u>y-intercepts are found by setting x=0</u>
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4 0
3 years ago
Determine the standard form of the equation of the line that passes through ( -5,0 ) ( 0 ,-9)
insens350 [35]

The general form for a line through two points (a,b) and (c,d) is

(c-a)(y-b)=(d-b)(x-a)

This is better than the slope forms because it works in the no slope case, as does the standard form.

If you haven't seen it before, it works because when (x,y)=(a,b) we get (c-a)(b-b)=(d-b)(a-a), both sides zero, and when (x,y)=(c,d) we get (c-a)(d-b)=(d-b)(c-a), clearly equal sides.

Here we have

(0 - -5)(y - 0) = (-9 - 0)(x - - 5)

5y = -9(x+5)

5y = -9x - 45

9x + 5y = -45

Ironically there are two standards for standard form; one with the constant alone on the right and one with the whole thing equal to zero.  I like the constant alone.

Answer: 9x + 5y = -45

Check:

We check each point is on the line

(-5,0)

9(-5) + 5(0) = -45, good

(0, -9)

9(0) + 5(-9) = -45, good again


5 0
3 years ago
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