Question

A rectangle with a perimeter of 40m is 2m7, longer than it is wide. Determine the dimensions of the rectangle.

Answer 1

Hello from MrBillDoesMath!

Answer:

9, 11

Discussion:

From the attachment,

P = w + l + w + l

  = 2w + 2l                       => as l = w + 2

  = 2w  + 2( w+2)        

  = 4w + 4

  = 40        (given value)

4w + 4= 40                => subtract 4 from both sides

4w = 40 -4 = 36        => divide both sides by 4

w = 36/4 = 9

This implies that l = w+2 = 9 + 2 = 11

 

Thank you,

MrB