A rectangle with a perimeter of 40m is 2m7, longer than it is wide. Determine the dimensions of the rectangle.
1 answer:
Hello from MrBillDoesMath!
Answer:
9, 11
Discussion:
From the attachment,
P = w + l + w + l
= 2w + 2l => as l = w + 2
= 2w + 2( w+2)
= 4w + 4
= 40 (given value)
4w + 4= 40 => subtract 4 from both sides
4w = 40 -4 = 36 => divide both sides by 4
w = 36/4 = 9
This implies that l = w+2 = 9 + 2 = 11
Thank you,
MrB
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