y = x - 3
1. Subtract 7 from the right to the left.
* 4y = 4x - 12
2. Divide the 4 (constant) next to the 'y' to the other side.
* y = 4/4x - 12/4
* y = x - 3
Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.
Answer:
There are a 25% probability that Christine fails the course.
Step-by-step explanation:
We have these following probabilities:
A 50% probability that Christine finds a tutor.
With a tutor, she has a 10% probability of failling.
A 50% probability that Christine does not find a tutor.
Without a tutor, she has a 40% probability of failing.
Probability that she fails:
10% of 50%(fail with a tutor) plus 40% of 50%(fail without a tutor). So

There are a 25% probability that Christine fails the course.
9514 1404 393
Answer:
No
Step-by-step explanation:
The initial balance at the beginning of the year is not zero, so the balance is not proportional to the time since the beginning of the year.
__
A proportional relationship always starts at zero when the independent variable is zero.
There is no way to divide them because 133 is odd, so 133 divided by 8 would be 16.625.