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givi [52]
3 years ago
5

A district-wide test is used to measure math attitude in freshmen in high school students, with a mean of 78 and a standard devi

ation of 12. Thirty-six selected freshmen took the test and their mean score was 85. You are tasked to examine if these students are significantly different from the district test group
Mathematics
1 answer:
fiasKO [112]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that

Population mean \mu=78

std deviation \sigma =12  = 12

sample size n =36

Sample mean = \bar x = 85

H_0: \bar x = 85\\H_a: \bar x \neq 85

(Two tailed test)

Mean difference = 7

Std error =\frac{\sigma}{\sqrt{n} } \\=\frac{12}{6} \\=2

Since population std dev is known and n>30 we use Z test

Z statistic = \frac{7}{2} =3.5\\

p value <0.001

Since p value is <0.01, at 1% significance level, we reject H0.

There is significant difference between sample mean and population mean.

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Answer:

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3 years ago
You are designing the garden of your dream and you are going to start with a blank canvas. That means killing everything before
Aleks [24]

Answer:

2.5 bottles or 3 bottles

Step-by-step explanation:

Given that :

Dimension of lot :

22.5 yds by 20.4 yds

Area of lot = 22.5 * 20.4 = 459 yd²

Volume per bottle of herbicide = 12 fl oz

1.1 fl oz combined with water treats an area of 155 ft²

Number of 1.1 fl oz from 12 fl oz that can be obtained : 12 / 1.1 = 10.90

1 yard² = 9 feet²

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Number of 151 feet² that can be obtained from 4131 feet²

4131 feet² / 155 ft²

= 27.3576 times

= 27.3576 / 10.909

= 2.507

This means he'll have to buy a minimum of 3 bottles if a fraction of a bottle can't be purchased.

7 0
3 years ago
The bacteria took 1 hour and 40 minutes to fill the initial bottle. Explain how it only took 10 minutes to fill 3 additional emp
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6 0
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a munfuctor of medical supplies produces 1 liter of bags of saline solution. the cost to produce x thousand bags of saline is gi
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8 0
3 years ago
A professor finds that the average SAT score among all students attending his college is 1150 ± 150 (μ ± σ). He polls his class
solniwko [45]

Answer:

Step-by-step explanation

Hello!

Be X: SAT scores of students attending college.

The population mean is μ= 1150 and the standard deviation σ= 150

The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.

If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:

H₀: μ = 1150

H₁: μ ≠ 1150

α: 0.05

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)

Z_{H_0}= \frac{1200-1150}{\frac{150}{\sqrt{25} } } = 1.67

The p-value for this test is  0.0949

Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.

I hope it helps!

7 0
3 years ago
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