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givi [52]
3 years ago
5

A district-wide test is used to measure math attitude in freshmen in high school students, with a mean of 78 and a standard devi

ation of 12. Thirty-six selected freshmen took the test and their mean score was 85. You are tasked to examine if these students are significantly different from the district test group
Mathematics
1 answer:
fiasKO [112]3 years ago
7 0

Answer:

Step-by-step explanation:

Given that

Population mean \mu=78

std deviation \sigma =12  = 12

sample size n =36

Sample mean = \bar x = 85

H_0: \bar x = 85\\H_a: \bar x \neq 85

(Two tailed test)

Mean difference = 7

Std error =\frac{\sigma}{\sqrt{n} } \\=\frac{12}{6} \\=2

Since population std dev is known and n>30 we use Z test

Z statistic = \frac{7}{2} =3.5\\

p value <0.001

Since p value is <0.01, at 1% significance level, we reject H0.

There is significant difference between sample mean and population mean.

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John hosts an art workshop on the weekends. He has an average of 14 students in each session and charges a fee of $12 per sessio
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Answer: c(x)=-2 x2 + 16x + 168

Step-by-step explanation: I hope this helps if im wrong im srry!

8 0
4 years ago
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One column of numbers consists of 28,42,14. When the digits of the numbers are added together, the result is 2+8+4+2+1+4=21, and
AVprozaik [17]

Option D. What we can conclude is that  If the end result from the second column is not 3, then the sum of the numbers in the first column is not equal to the sum of the numbers in the second column.

<h3>How to solve for the solution</h3>

An operation is done on a first column of numbers. When this operation is repeated on the second column, we would have option D.

If the sum of the numbers that are in the third can be seen to be greater than three, then the sums are not going to be seen as equal

Read more on this column of numbers here

brainly.com/question/1435706

#SPJ1

<h3>Complete question</h3>

One column of numbers consists of 28, 42, and 14. When the digits of the numbers are added together, the result is 2 + 8 + 4 + 2 + 1 + 4 = 21, and when the digits of 21 are then added together, the end result is 2 + 1 = 3. If the same process is performed on the numbers in a second column, what can be concluded?

A. If the end result from the second column is also 3, then the sum of the numbers in the first column is not equal to the sum of the numbers in the second column.

B. If the end result from the second column is not 3, then the sum of the numbers in the first column is equal to the sum of the numbers in the second column.

C. If the end result from the second column is also 3, then the sum of the numbers in the first column is equal to the sum of the numbers in the second column.

D. If the end result from the second column is not 3, then the sum of the numbers in the first column is not equal to the sum of the numbers in the second column.

7 0
2 years ago
Please help <br> i really appreciate it
mars1129 [50]

Answer:

C

Step-by-step explanation:

i litterally just did this question i believe

8 0
3 years ago
Y−5x=3 solve for y please
Korvikt [17]

Answer: INDEiAaaaaaaaaaaaaaaa

4 0
3 years ago
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If there are 1500 guests, only 1 of them brought a coupon for free admission to the carnival?
wlad13 [49]
So 1/50 brought the pass
x out 1500
1/50 = x/1500
cross multiply
1500 = 50x
divide both sides by 50
30 = x

You can expect for 30 out of the 1,500 to receive free admissions. 

Hope this helps 
4 0
3 years ago
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