All categories

2 years ago

the coordinate of J' after a reflection of the triangle is about the line y= -x. The coordinates of J is (-2,-1)

Mathematics

1 answer:

Nuetrik [128]2 years ago

3 0

The reflection line is located at y = -x

For point J, x is -2, so y = -(-2), which equals 2.

When it is a reflection across Y, the X values remain the same.

Find the distance of the Y point to the reflection line,

The distance from -1 to 2 is 3 units.

The new point needs to be the same distance from the reflection line.

2 + 3 units = 5.

Point J' would be (-2,5)

You might be interested in

What is the solution for the =.

liq [111]

Answer:

solution for n is $\frac{-13}{4}$

Step-by-step explanation:

Given an equation containing one variable n.

The equation is as follows:

$\frac{-5}{2} =\frac{3}{4} +n$

To solve for n we can subtract 3/4 from both the sides

The result is

$\frac{-5}{2} -\frac{3}{4} =n\\Take LCD as 4\\\\frac{-10-3}{4} =n$

Verify:

Substitute the answer in the given equation.

$\frac{-5}{2} =\frac{3}{4} -(\frac{13}{4} )$

Both sides equal thus proving our correctness of answer.

3 0

3 years ago

What is the equation of a horizontal line that has a y-intercept of -5?

Cloud [144]

Check the picture below.

6 0

3 years ago

How do you divide 6,348 divided by 52, using compatible numbers??

mario62 [17]

122.0769 hopefully I helped you out

8 0

3 years ago

If -5x-y=1 is a true equation, what would be the value of 5(-5x-y)?

Tanzania [10]

Answer:

-25-5x-5y

Step-by-step explanation:

7 0

3 years ago

1+000 +0000 - 1 what is the best answer

creativ13 [48]

Answer:

It's 0 I think I'm not sure (I'm sure it's 0 but That's what I always say to humble myself so)

Step-by-step explanation:

5 0

2 years ago

the coordinate of J' after a reflection of the triangle is about the line y= -x. The coordinates of J is (-2,-1)​

the coordinate of J' after a reflection of the triangle is about the line y= -x. The coordinates of J is (-2,-1)