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Alona [7]
3 years ago
6

Solve 3x^2 = -12x - 15

Mathematics
1 answer:
Levart [38]3 years ago
6 0

The answer is no real solution

Step-by-step explanation:

Let's solve your equation step-by-step.

3x2=−12x−15

Step 1: Subtract -12x-15 from both sides.

3x2−(−12x−15)=−12x−15−(−12x−15)

3x2+12x+15=0

Step 2: Use quadratic formula with a=3, b=12, c=15.

x=

−b±√b2−4ac

2a

x=

−(12)±√(12)2−4(3)(15)

2(3)

x=

−12±√−36

6

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Considering the expression x/2 + y2. Which statements are true?Mark all that apply.
Svet_ta [14]

Answer:

  D.  8/2 +(-10)² = 104

Step-by-step explanation:

To find which statements are true, evaluate the expression for the given variable values. You do this by putting the numbers in place of the respective variables, then doing the arithmetic.

The respective expression values are ...

  A 83 ≠ 37 . . . . (4/2) +9² = 2 +81 = 83

  B 31 ≠ 61

  C 52 ≠ 61

  D 104 =104 . . . . true statement

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I find it less tedious to write a function into a calculator or spreadsheet and let it do the repetitive math. Examples of the calculation are shown above.

7 0
3 years ago
What are the numbers after 10 8 7 9​
kramer

Answer:

Step-by-step explanation:

ven numbers always end with a digit of 0, 2, 4, 6 or 8.

2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30 are even numbers.

Odd numbers always end with a digit of 1, 3, 5, 7, or 9.

1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 are odd numbers.

3 0
3 years ago
Which of the following statements about JK and JL is true?
bulgar [2K]

Answer:

14

Step-by-step explanation:

5 0
3 years ago
The length of a rectangle is 5959 inches greatergreater than twice the width. if the diagonal is 2 inches more than the​ length,
lorasvet [3.4K]

Length: 2w + 59

width: w

diagonal: (2w + 59) + 2  = 2w + 61

Length² + width² = diagonal²

(2w + 59)² + (w)² = (2w + 61)²

(4w² + 118w + 3481) + w²  = 4w² + 122w + 3721

5w² + 118w + 3481 = 4w² + 122w + 3721

w² + 118w + 3481 = 122w + 3721

w² - 4w + 3481 = 3721

w² - 4w - 240 = 0

a = 1, b = -4, c = -240

w = [-(b) +/- \sqrt{(b)^{2}  - 4(a)(c) }]/2(a)

 = [-(-4) +/- \sqrt{(-4)^{2}  - 4(1)(-240) }]/2(1)

   =  [4 +/- \sqrt{(16  + 960) }]/2        

  = [4 +/- \sqrt{(976) }]/2  

  = [2 +/- 4\sqrt{(61) }]/2  

  = 1 +/- 2\sqrt{(61) }

since width cannot be negative, disregard  1 - 2√61

w = 1 + 2√61  ≈ 16.62

Length: 2w + 59  =  2(1 + 2√61) + 59  = 2 + 4√61 + 59  =  61 + 4√61  ≈ 92.24

Answer: width = 16.62 in, length = 92.24 in

7 0
3 years ago
D
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The slope of y=-2x+4 is -2
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