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3 years ago

QUESTION

Mathematics

2 answers:

Natalka [10]3 years ago

7 0

I agree with Karen!!!!!

garri49 [273]3 years ago

3 0

Answer:

Step-by step

What do we already know about the equation?

We know that they EACH bought a hockey puck($17) and 2 shirts

Half of 214 is 107. So they had to have spent 107 separately

So we make the equation and let s represent shirts

2s + 17 = 107

- 17 -17

2s= 90. DIVIDE by 2

s = 45

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PLEASE PLEASE I NEED HELP ASAP

Sidana [21]

AE = AC = 4

m<CAB = 60 (equilateral triangle)
m<CAE = 90 (square)

m<BAE = 150 (= 60 + 90)

Triangle BAE is isosceles since AB = AE;
therefore, m<AEB = m<ABE.

m<AEB + m<ABE + m<BAE = 180

m<AEB + m< ABE + 150 = 180

m<AEB + m<AEB = 30

m<AEB = 15

In triangle ABE, we know AE = AB = 4;
we also know m<BAE = 150, and m<AEB = 15.

We can use the law of sines to find BE.

BE/(sin 150) = 4/(sin 15)

BE = (4 sin 150)/(sin 15)

BE = 7.727

3 0

3 years ago

Please help thanks!!

marin [14]

Number one because...

2(x-1)>=-12

2x-2>=-12

2x>=-10

X>=-5

7 0

3 years ago

Whats 7, −6, 4, −10, 3 least to greatest

exis [7]

Answer:

-10, -6, 3, 4, 7

Step-by-step explanation:

Hope it helps ^^

4 0

3 years ago

The axis of symmetry for a function in the form f(x) = x2 + 4x − 5 is x = −2. What are the coordinates of the vertex of the grap

Studentka2010 [4]

Answer:

D) $(-2,-9)$

Step-by-step explanation:

<u>Vertex Form of a Vertical Parabola:</u>

$y=a(x-h)^2+k$

Vertex -> $(h,k)$

Axis of Symmetry -> $x=h$

Vertical Scale Factor -> $a$

To turn $f(x)=x^2+4x-5$ into vertex form, we need to complete the square on the right side
Therefore, if $f(x)=0$ , then $0+9=x^2+4x-5+9$ completes the square on the right side
This becomes $9=(x+2)^2$
This means that our function in vertex form is $f(x)=(x+2)^2-9$