Answer: 109.1 degrees
Step-by-step explanation:
To find the angle between the given vectors, we will use the formula below:
Cos(θ) = (U.V)/ |U|.|V|
Where
U = 13i - 8j
V = 2i + 9j
U.V = (2x13) + (-8×9)
U.V = 26 - 72
U.V = - 46
|U| = sqrt ( 13^2 + 8^2)
= sqrt ( 233) = 15.264
|V| = sqrt( 2^2 + 9^2)
= sqrt ( 85 ) = 9.22
Substitute all the value of the parameters into the formula
Cos ø = -46 / (15.3 × 9.2)
Cos ø = - 46 / 140.72
Cos Ø = - 32687
Find the cos inverse of the value
Ø = cos^-1( -32687)
Ø = 109.079 degrees
Therefore, the angle between the given vectors to the nearest tenth of a degree is 109.1 degrees
Answer:
Step-by-step explanation:
(X+4)1999=1
Open the bracket by multiplying 1999 by the values in the bracket
1999x + 7996 = 1
Collect like terms
1999x = 1-7996
1999x = -7995
Divide both sides by 1999
X = -3.99
Range: largest number minus the smallest number
39 - 19 = 20
your range is 20
Mean: add all of the numbers and divide by the amount of numbers there are.
26+19+23+39+31+34+23+25= 220
220/8 = 27.5
your mean is 27.5
hope this helps
Answer:
A
Step-by-step explanation:
It has the smallest surface with an increase in height
