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givi [52]
3 years ago
9

The fifth,ninth and sixteenth term of a Linear sequence are the consecutive term of an exponential sequence. Find the common dif

ference of the linear sequence. Also show that the 21st, 37th and 65th terms of the sequence are consecutive terms of the exponential sequence whose common ratio is =7/4​
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

vfbg

Step-by-step explanation:

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If the area of a circle is 58 square feet, find the circumference
Blizzard [7]

Answer:

C≈27 feet

Step-by-step explanation:

A=πr²

A/π=r²

√A/π =r or –√A/π=r (refused)

then r =√(A/π) =√(58/π) =4.297829403 feet

C=2πr=2π(4.297829403)=27.00405856≈27 feet

7 0
3 years ago
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Dominik [7]
If 2 points lie in a plane, the line containing those opints lies in the same plane
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3 years ago
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Suppose Richard walks 1 kilometer every 10 minutes. How many meters further can he walk in 1 hour at this new rate?
Andrej [43]
Richard walks
1 kilometer : 10 minutes

That would mean 

6 kilometers : 60 minutes

<span>Hope that helps and correct me if I'm wrong!</span>
5 0
3 years ago
Find an equation for the line that passes through the points (-5,-5) and (1,4)
Andreas93 [3]

The general line through (a,b) and (c,d) is

(c-a)(y-b)=(d-b)(x-a)

Here that's

(1 - - 5)(y - - 5) = (4 - -5)(x - - 5)

6(y+5)=9(x+5)

6y + 30 = 9x + 45

-15 = 9x - 6y

3x - 2y = -5

Answer: 3x - 2y = -5

We could put that in slope intercept form,

2y = 3x + 5

y = (3/2) x + 5/2

Answer: y = (3/2) x + 5/2

3 0
3 years ago
4a/3-b/4=6<br> 5a/6+b=13<br> Solve linear system by elimination
kondor19780726 [428]
\bf \cfrac{4a}{3}-\cfrac{b}{4}=6&#10;\qquad \qquad &#10;\cfrac{5a}{6}+b=13&#10;\\\\\\&#10;\textit{let us remove the denominators off those folks}\\&#10;\textit{by multiplying the first one by 12, both sides}\\&#10;\textit{and the second one by 6, both sides, thus}&#10;\\\\\\&#10;12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72&#10;\\\\\\&#10;6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78

\bf  \textit{now, let's do the elimination}&#10;\\\\&#10;&#10;\begin{array}{llll}&#10;16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\&#10;5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\&#10;&&--------\\&#10;&&58a+0\quad=372&#10;\end{array}

solve for "a", once you get "a", plug it back into either equation to get "b"
3 0
3 years ago
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